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3 years ago

The ratio of two numbers is 8/1 and the difference of the numbers is 280. What is the larger of the two numbers?

Mathematics

1 answer:

Gala2k [10]3 years ago

7 0

<h2>The correct answer is 320.</h2>

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Jai Narayan sells two radio sets for 2288 each.

san4es73 [151]

Answer:

Step-by-step explanation:

S.P of each radio=$ 2288

Total S.P= $2\times 2288=$ $4576

Gain=10%

Lose=10%

C.P= $\frac{S.P\times 100}{100+gain(in\;percent)}$

C.P= $\frac{S.P\times 100}{100-loss(in\;percent)}$

By using the formula

C.P of one radio= $\frac{2288\times 100}{110}=$ $2080

C.P of another radio= $\frac{2288\times 100}{100-10}$ =$2542.2

Total C.P of two radios=2080+2542.2=$4622.2

Total C.P >Total S.P

Loss=S.P-C.P

Loss=4622.2-4576=$46.2

Loss%= $\frac{Loss}{C.P}\times 100$

Loss %= $\frac{46.2}{4622.2}\times 100=$ 1%

Hence, his loss 1%

5 0

3 years ago

At what rate per annum ci will RS 2000 amount to RS 2315.35 in 3 years

Mashutka [201]

<u>ANSWER: </u>

Rate per annum at which CI will amount from RS 2000 to RS 2315.35 in 3 years is 5%

<u>SOLUTION: </u>

Given,

P = RS 2000

C.I = RS 2315.35

T = 3 years

We need to find the rate per annum. i.e. R = ?

We know that,

When interest is compound Annually:

$Amount $=\mathrm{P}\left(1+\frac{\mathrm{R}}{100}\right)^{n}$$

Where p = principal amount

r = rate of interest

n = number of years

$2315.35=2000 \times\left(1+\frac{R}{100}\right)^{3}$

$\left(1+\frac{R}{100}\right)^{3}=\frac{2315.35}{2000}$

$\left(1+\frac{R}{100}\right)^{3}=1.157$

$1+\frac{R}{100}=\sqrt[3]{1.157}$

$1+\frac{R}{100}=1.0500$

$\frac{R}{100}=1.05-1$

$\frac{R}{100}=0.05$

R = 5%

Hence, rate per annum is 5 percent.

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