Answer:
x=13
Step-by-step explanation:
9^2 * 27^3 = 3^x
We need to get each term with a base of 3
9^2 = (3^2) ^2
We know that a^b^c = a^(b*c)
(3^2) ^2 = 3^(2+2) = 3^4
27^3 = (3^3) ^3 = 3^(3*3) = 3^9
Replacing these in the original equation
3^4 * 3^9 = 3^x
We know that a^b *a^c = a^(b+c)
3^4 * 3^9 =3^(4+9) = 3^13 = 3^x
The bases are the same, so the exponents must be the same
x=13
Answer:
14y=mxc I'm I right kwkbs
Answer:
6
Step-by-step explanation:
-9x^3-72x^2+36=3x^3+x^2-3x+8 Add 9x^3 to both sides.
-72x^2 + 36 = 3x^3 + 9x^3 + x^2 - 3x + 8 Add 72x^2 to both sides
36 = 12x^3 + 73x^2 - 3x + 8 Subtract 36 from both sides.
0 = 12x^3 + 73x^2 - 3x - 28
It does factor, but it is not very nice.
(x + 6.06)(x - 6.09)(x + 0.632)
If there is any kind of error please report it in a note below.
