The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Answer: Infinitely many solutions when we graph this it comes out as one straight line also try using Desmos it helps with equations like this by graphing them for you! -Your friend, Bill Cipher
Step-by-step explanation: Have a great Valentines day <3
Answer:
28, 32, 36
Step-by-step explanation:
If you multiply each 7, 8, and 9 by 4 you get 28, 32, and 36. The sum of those numbers is 96.
Answer & Step-by-step explanation:
Using the information given in the question we can form the following 3 equations (in the order of the first 3 sentences)
w = 2h (twice the price)
t = h - 4 ($4 less)
3w + 2h + 5t = 136 (total purchasing and cost)
We can solve all 3 equations for h first, by substituting the first two equations, into the third equations w and t
3(2h) + 2h + 5(h-4) = 136
Simplify
6h + 2h + 5h - 20 = 136
13h = 136 + 20
13h = 156
h = 156/13
h = $12
Using this information, we can solve for w and t
w = 2h
w = 2(12)
w = $24
And finally
t = h - 4
t = 12 - 4
t = $8