Before 1995, three-digit area codes for the united states had the following restrictions:

The following function represents the value of a car, in dollars, after x years:

Assoli18 [71]

Answer:

Option D.The decrease in the value of the car, which is 8%

Step-by-step explanation:

we have a exponential function of the form

$f(x)=a(b)^{x}$

where

y is the value of the car

x is the time in years

a is the initial value

b is the base

r is the rate of decrease

b=1+r

In this problem we have

a=$24,000 initial value of the car

b=0.92

so

0.92=1+r

r=0.92-1=-0.08=-8%-----> is negative because is a rate of decrease

8 0

2 years ago

Read 2 more answers

one end of a ten- foot ladder is four feet from the base of a wall . how high on the does the top of the ladder touch ??

Jet001 [13]

Answer:

9,2 feet

Step-by-step explanation:

Use the Pythagorean theorem: height= sqrt(10^2-4^2)= sqrt(84) =9,2 ~

sqrt Is Square root btw

8 0

2 years ago

What is the speed of a runner who completes the 800 m race in one minute and 40 seconds?

skelet666 [1.2K]

Answer: 8 m/s

First let’s convert the time to seconds. There are 69 seconds in a minute so 1 minute and 40 seconds is 60 +40 second which totals to 100 seconds
Now to get the speed in meters per second we divide the total meters run by the total seconds
So the speed will be 800m/100s = 8m/s

7 0

3 years ago

4/5 divided by 1/3 plus 1/5 minus 3/5

r-ruslan [8.4K]

Answer:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

Step-by-step explanation:

Considering the expression

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

Solution Steps:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

as

$\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}$

so

$=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}$

$=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}$

join $\frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}$

so

$=\frac{4}{5\left(-\frac{1}{15}\right)}$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{4}{-5\cdot \frac{1}{15}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}$

$=-\frac{4}{5\cdot \frac{1}{15}}$

$\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}$

so

$=-\frac{4}{\frac{1}{3}}$

$\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}$

so

$=-\frac{12}{1}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=-12$

Therefore

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

4 0

2 years ago

What is the product of (2x-1)(x+4)

Novay_Z [31]

Answer:

$\large\boxed{(2x-1)(x+4)=2x^2+7x-4}$

Step-by-step explanation:

$(2x-1)(x+4)\qquad\text{use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\=(2x)(x)+(2x)(4)+(-1)(x)+(-1)(4)\\\\=2x^2+8x-x-4\qquad\text{combine like terms}\\\\=2x^2+(8x-x)-4\\\\=2x^2+7x-4$

4 0

3 years ago