Alright, so we'd use the combinations with repetition formula, so we choose from 4 schools to distribute to and distribute 8 blackboards. It's then
( 8+4-1)!/8!(4-1)!=11!/(3!*8!)=165
For at least one blackboard, we first distribute 1 to each school and then have 4 blackboards left, getting (4+4-1)!/4!(4-1)!=7!/(4!*3!)=35
Fifty-five and twelve hundreths
Answer:
77381 is your answer
Step-by-step explanation:
Answer:
P ( 3, - pi/3 + 2 pi n) or P ( -3 , -pi/3 + pi(2 n +1))
Step-by-step explanation:
P ( 3, - pi/3)
We can circle 2pi n around the circle and be back at the same polar coordinate
P ( 3, - pi/3 + 2 pi n)
or we can flip the radius to a negative and add pi to the theta
P ( -3, - pi/3 + pi)
Then we can circle 2pi n around the circle and be back at the same polar coordinate
P ( -3 , -pi/3 + 2 pi n +pi)
P ( -3 , -pi/3 + pi(2 n +1))
Answer:
SSS Congruence Theorem
Step-by-step explanation: