The center of the circle is the midpoint of the segment between the endpoints. We can determine the location of the center by this vectorial expression:

$C(x,y) = \frac{1}{2}\cdot R_{1}(x,y)+ \frac{1}{2}\cdot R_{2}(x,y)$ (1)

Where:

$C(x,y)$ - Center.

$R_{1} (x,y)$ , $R_{2} (x,y)$ - Location of the endpoints.

If we know that $R_{1} (x,y) = (-2,10)$ and $R_{2} (x,y) = (6,-4)$ , then the location of the center of the circle is:

$C(x,y) = \frac{1}{2}\cdot (-2,10)+\frac{1}{2}\cdot (6,-4)$

$C(x,y) = (-1, 5) + (3, -2)$

$C(x,y) = (2, 3)$

The center of the circle is $C(x,y) = (2, 3)$ .

8 0

3 years ago

70 of 38.20 is what<br><br> Have to write at least 20 words sooo

Nana76 [90]

26.74. I’m assuming you are asking what 70% of 38.20 is. 38.20 x 0.70 = 26.74

7 0

2 years ago

The table shows the cost in dollars, y, for shipping x number of chargers and electronic tablets.

Soloha48 [4]

The answer is y=6.00x+12.00,if i’m wrong then i’m so sorry

7 0

3 years ago