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4 years ago

-5/6 and 8/3 on a number line

Mathematics

1 answer:

ki77a [65]4 years ago

6 0

Answer:

I hope this helps. This is what a number line looks like and how you do it.

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Anna walks dogs to earn money. She saves $4 for every $10 she earns.

CaHeK987 [17]

Answer:

it that all the question

Step-by-step explanation:

3 0

3 years ago

If the discriminant is 22, then the roots of the quadratic equation are ________________.

Allisa [31]

Since the discriminant given has a value that is greater than zero, hence the roots of the quadratic equation are real and distinct.

<h3>Discriminant of a quadratic equation</h3>

Quadratic equation is an equation that has a leading degree of 2. The discriminant is used to determine the nature of the equation

If D > 0 , the roots of the quadratic equation are real and distinct.

If D < 0 , the roots of the quadratic equation are complex

Since the discriminant given has a value that is greater than zero, hence the roots of the quadratic equation are real and distinct.

Learn more on discriminant here: brainly.com/question/2507588

#SPJ1

4 0

2 years ago

HELP PLEASE!!!!!!!!

lana [24]

Answer:

Step-by-step explanation:

If you divide 2,727 miles by 27 miles per gallon you will get the number of gallons: = 101. Then, multiply the number of gallons by the cost per gallon: 101(4.04) = 408.04. This gives the cost of gas for this car to travel 2,727 typical miles.

4 0

4 years ago

Show that the line integral is independent of path by finding a function f such that ?f = f. c 2xe?ydx (2y ? x2e?ydy, c is any p

Juli2301 [7.4K]

I'm reading this as

$\displaystyle\int_C2xe^{-y}\,\mathrm dx+(2y-x^2e^{-y})\,\mathrm dy$

with $\nabla f=(2xe^{-y},2y-x^2e^{-y})$ .

The value of the integral will be independent of the path if we can find a function $f(x,y)$ that satisfies the gradient equation above.

You have

$\begin{cases}\dfrac{\partial f}{\partial x}=2xe^{-y}\\\\\dfrac{\partial f}{\partial y}=2y-x^2e^{-y}\end{cases}$

Integrate $\dfrac{\partial f}{\partial x}$ with respect to $x$ . You get

$\displaystyle\int\dfrac{\partial f}{\partial x}\,\mathrm dx=\int2xe^{-y}\,\mathrm dx$
$f=x^2e^{-y}+g(y)$

Differentiate with respect to $y$ . You get

$\dfrac{\partial f}{\partial y}=\dfrac{\partial}{\partial y}[x^2e^{-y}+g(y)]$
$2y-x^2e^{-y}=-x^2e^{-y}+g'(y)$
$2y=g'(y)$

Integrate both sides with respect to $y$ to arrive at

$\displaystyle\int2y\,\mathrm dy=\int g'(y)\,\mathrm dy$
$y^2=g(y)+C$
$g(y)=y^2+C$

So you have

$f(x,y)=x^2e^{-y}+y^2+C$

The gradient is continuous for all $x,y$ , so the fundamental theorem of calculus applies, and so the value of the integral, regardless of the path taken, is

$\displaystyle\int_C2xe^{-y}\,\mathrm dx+(2y-x^2e^{-y})\,\mathrm dy=f(4,1)-f(1,0)=\frac9e$

8 0

3 years ago

Alexis is making bread dough.The recipe requires 3/4 cup of flour and 1 2/5 teaspoon of salt. To maintain the ratio,how much sal

tekilochka [14]

Answer:

16/5 teaspoons

Step-by-step explanation:

1/4 cups of flour uses 4/15 teaspoon so 4/15 x 4 is 16/5

7 0

3 years ago