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3 years ago

Could someone please help me with this math question

Mathematics

2 answers:

Oksana_A [137]3 years ago

7 0

Answer:

1/2

Step-by-step explanation:

Yuri [45]3 years ago

5 0

Answer:

1) 1/2

Step-by-step explanation:

first you must put "y" on its own, so the equation would then look like:

a) 4y = 2x - 18 or b) -4y = -2x + 18,

either or works, then you divide both sides of the equation by the coefficient on y, where on a it is 4 and on b it is -4.

Whatever you get, you would end up with the same answer,

y = 1/2x -18/4,

thus the slope would be 1/2

You might be interested in

Find the 12th term of the arithmetic sequence given a3=116 and a7=180

SOVA2 [1]

Answer:

Step-by-step explanation:

nth term = a +(n-1)d

a3 = 116 ; a + 2d = 116 ---------(i)

a7 = 180; a + 6d = 180 -------(ii)

multiply (ii) by -1. so a will be eliminated

a + 2d = 116 ---------(i)

(ii)*-1 -a - 6d = -180 -------(ii) { Now add the two equations}

- 4d = -64

d = -64/-4

d = 16

Plug in the value of d in equation (i),

a + 2*16 = 116

a + 32 = 116

a = 116 - 32

a = 84

12th term = 84 + 11* 16 = 84 + 176 = 260

5 0

4 years ago

Can someone please answer. There is a picture. There is only one problem. Thank you so much!!!

kvasek [131]

Hello,

Answer D

x²/25+y²/16=1

5 0

4 years ago

Rewrite the system of linear equations as a matrix equation AX = B.

iren2701 [21]

Answer:

$\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]$

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

$\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]$

And the vector of vriables (X) is:

$\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]$

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

$\left[\begin{array}{ccc}5\\6\\7\end{array}\right]$

In conclusion, AX=B is:

$\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]$

7 0

4 years ago

Katy buys 4 dvds every 2 weeks. How many will she buy in 12 weeks?

Tom [10]

She buys 24 dvds in 12 weeks.

3 0

3 years ago

Read 2 more answers

Solve the system of equations.in this form: (x, y) -5y + 8x = -18 5y + 2x = 58

Gre4nikov [31]

If we add the equations it looks like
-5y + 8x + 5y + 2x = -18+58
so 10x=40
so x=40/10=4
now let's replace x by 4 in the second equation
5y +2*4=58
5y=58-2*4=58-8=50
so y=50/5=10
so (x, y) = (2, 10)

5 0

4 years ago

Read 2 more answers