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Katyanochek1 [597]
3 years ago
9

I will mark the Brainiest!!

Mathematics
1 answer:
lukranit [14]3 years ago
6 0
1st pic

answer
D. Yes. triangle JKL similar to triangle STV. SF is 6

----------
2nd pic
answer is A.
No because length of corresponding sides are not proportional

--------------

3rd pic

34/17 = 12
so
x  = 30/2 = 15
y = 16/2 = 8

answer
x = 15
y = 8

--------------

4th pic

28/14 = 2
so
x = 42/2 = 21
y = 56/2 = 28
z = 42/2 = 21

answer

x = 21
y = 28
z = 21
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Can anyone figure this out?
Verizon [17]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill


\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}


now that we know how long each one is, let's plug those in Heron's Area formula.


\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18

5 0
4 years ago
A bank requires a four-digit access code for each account. The access code is generated using the digits 0–9, and the digits can
yaroslaw [1]

Each number in the code can be 1 of 10 numbers.


The total number of possible combinations is 10 * 10 * 10 * 10 = 10,000

The probability of getting 1234 would be 1/10,000

4 0
3 years ago
Read 2 more answers
(5x+2)[3(x+14)]<br><br> what is the value of x
Julli [10]

Here it is. You can also use the quadratic equation to find the answer.

5 0
3 years ago
Help!!!please:((( I don’t understand
puteri [66]
Find the probability of Red/small.

Red = large + small
large = 8
Small = 12
Plug in 8 for large, and 12 for small
Red = 8 + 12
Red = 20
Now we know that the total red = 20

Do the same with small

3 small blue
12 small red

Small = blue + red
Small = 3 + 12
Small = 15

Note that red is first then small. Put red over small
Remember that red = 20, small = 15

20/15 is the fraction you need.

However, note that it says "reduce your answer" at the bottom

Divide 5 from numerator and denominator

(20/15)/(5/5) = 4/3

4/3 is your answer

hope this helps


4 0
4 years ago
Read 2 more answers
An engineer is planning a new water pipe installation. The circular pipe has a diameter of d=20\text{ cm}d=20 cmd, equals, 20, s
aivan3 [116]

Answer: The answer is 314.28 cm² (approx.).


Step-by-step explanation:  Given that an engineer is going to install a new water pipe. The diameter of this circular pipe is, d = 20 cm.

We need to find the area 'A' of the circular cross-section of the pipe.

Given, diameter of the circular section is

\textup{d}=20~\textup{cm}.

So, the radius of the circular cross-section will be

\textup{r}=\dfrac{\textup{d}}{2}=\dfrac{20}{2}=10~\textup{cm}.

Therefore, cross-sectional area of the pipe is

\textup{A}=\pi \textup{r}^2=\dfrac{22}{7}(10)^2=\dfrac{2200}{7}=314\dfrac{2}{7}=314.28~.~.~.~\textup{cm}^2.

Thus, the answer is 314.28 cm² (approx.).

4 0
4 years ago
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