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gladu [14]
3 years ago
13

Mr Dominguez spends three weeks training for a marathon. Every day he runs 1/2 mile more than the day before. If the first day h

e ran 6 miles, how many will he run on the 21st day?
Mathematics
1 answer:
barxatty [35]3 years ago
3 0
Answer: 16 miles


Explanation:
I believe it would be 16 miles, if he starts off at 6 miles on day one and goes up 1/2 mile every day, he would be up a mile every other day, basically on day 3 he would be at 7 and day 5 at 8 miles, if the pattern continues he would be at 16 miles by day 21.
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Komok [63]
I think answer should be d. Please give me brainlest I hope this helps let me know if it’s correct or not okay thanks bye
3 0
3 years ago
Read 2 more answers
HELP MARK AS BRAINLIST
aleksley [76]

Answer: Area for trapezoid= 1/2(4+5×1)=4.5 m

Area of triangle= Iam not exactly sure

hope this helped you a bit

Step-by-step explanation:

6 0
3 years ago
I have just one question, could someone please answer it?? (see linked file)
Annette [7]

The solution is x=1 and y=-2

Further explanation:

Given equations are:

\frac{7}{2}x-\frac{1}{2}y=\frac{9}{2}\\3x-y=5

Multiplying equation no. 1 with 2 will give us:

7x-y=9       Eqn 3

From equation no 2:

3x-y=5\\-y=5-3x\\y=3x-5

Putting the value of y in eqn 3

7x-(3x-5)=9\\7x-3x+5=9\\4x=9-5\\4x=4\\\frac{4x}{4}=\frac{4}{4}\\x=1\\Putting\ x=1\ in\ equation\ 2\\3(1)-y=5\\3-y=5\\-y=5-3\\-y=2\\y=-2\\

The solution is x=1 and y=-2

Keywords: Linear equations, Solution set

Learn more about linear equations at:

  • brainly.com/question/561665
  • brainly.com/question/537998

#LearnwithBrainly

8 0
3 years ago
A student took a system of equations, multiplied the first equation by 2 and the second equation by 3, then added the results to
egoroff_w [7]

Answer:

system 4.

Step-by-step explanation:

3x+6y=9

multiply by 2

6x+12y=18   ....(1)

-2x+-4y=4

multiply by 3

-6x-12y=12   ...(2)

add (1) and (2)

0+0=30

which is impossible .It has no solutions.

3 0
3 years ago
A manufacturer cuts squares from the corners of a rectangular plece of sheet metal that measures 2 inches by 7 inches (see Figur
Vladimir79 [104]

Answer:

The value of x that maximizes the volume enclosed by this box is 0.46 inches

The maximum volume is 3.02 cubic inches

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The volume of the open-topped box is equal to

V=LWH

where

L=(7-2x)\ in\\W=(2-2x)\ in\\H=x\ in

substitute

V=(7-2x)(2-2x)x

Convert to expanded form

V=(7-2x)(2-2x)x\\V=(14-14x-4x+4x^{2})x\\V=14x-14x^2-4x^2+4x^{3}\\V=4x^{3}-18x^{2} +14x

using a graphing tool

Graph the cubic equation

Remember that

The domain for x is the interval -----> (0,1)

Because

If x>1

then

the width is negative (W=2-2x)

so

The maximum is the point (0.46,3.02)

see the attached figure

therefore

The value of x that maximizes the volume enclosed by this box is 0.46 inches

The maximum volume is 3.02 cubic inches

8 0
3 years ago
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