Check the picture below.
so let's use those two points the line passes through to get its slope.
![\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-12}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-12-0}{4-2}\implies \cfrac{-12}{2}\implies -6](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B2%7D~%2C~%5Cstackrel%7By_1%7D%7B0%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B4%7D~%2C~%5Cstackrel%7By_2%7D%7B-12%7D%29%20%5C%5C%5C%5C%5C%5C%20slope%20%3D%20m%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%7B%20y_2-%20y_1%7D%7D%7B%5Cstackrel%7Brun%7D%7B%20x_2-%20x_1%7D%7D%5Cimplies%20%5Ccfrac%7B-12-0%7D%7B4-2%7D%5Cimplies%20%5Ccfrac%7B-12%7D%7B2%7D%5Cimplies%20-6)
Answer:
y<= 3x-1
Step-by-step explanation:
When it comes about inequalities, keep in mind the following
the < sign means that the regions is under whatever is to other side, and the > means that the region is above whatever is on the other side of the sign
So, we see for the graphic that there is a region below a line, this suggests us that there is a < sign implied
The other thing is that there is a convention in math, is the line is graphed using a dashed line, it meas that it is not part of the region, if the line is graphed using a solid line (a continued line) then the line is inside the region, hence there is a = sign implied.
So the answer is y<= 3x-1
I = 42t
When t = 5, I = 42*5 = 210
When t = 6, I = 42*6 = 252
When t = 7, I = 42*7 = 294
When t = 8, I = 42*8 = 336
When t = 9, I = 42*9 = 378
When t = 10, I = 42*10 = 420
The equation of a circle with center (h,k) and radius r is
![(x-h)^2+(y-k)^2=r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2)
convert it to that form by comleting the square for the x and y terms
or, we can just expand what we know
expand
![(x-a)^2+(y-b)^2=m^2](https://tex.z-dn.net/?f=%28x-a%29%5E2%2B%28y-b%29%5E2%3Dm%5E2)
and make it equal to 0
so expanding we get
![x^2-2ax+a^2+y^2-2by+b^2=m^2](https://tex.z-dn.net/?f=x%5E2-2ax%2Ba%5E2%2By%5E2-2by%2Bb%5E2%3Dm%5E2)
minus m^2 from both sides
![x^2-2ax+a^2+y^2-2by+b^2-m^2=0](https://tex.z-dn.net/?f=x%5E2-2ax%2Ba%5E2%2By%5E2-2by%2Bb%5E2-m%5E2%3D0)
arranging in decreasing power order with m² at the end
![x^2+y^2-2ax+-2by+a^2+b^2-m^2=0](https://tex.z-dn.net/?f=x%5E2%2By%5E2-2ax%2B-2by%2Ba%5E2%2Bb%5E2-m%5E2%3D0)
that is option A
answer is A
The answer is A (2) cause if you were to rotate it twice it’d go back to its original form