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3 years ago

8

CAN AN EXPERT< ACE< MODERATOR OR GENIUS HELPP ME WITT THIS PLSSSSSSSSSSSSSS!!!!!!!!!!!!!!!!!!!!!!!!

1 answer:

mixas84 [53]3 years ago

4 0

Answer:

3x^2-3x+8-9/x+1

Step-by-step explanation:

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Are all right triangles similar explain your answer

kolbaska11 [484]

I think the answer is yes

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3 years ago

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My mom's car gets 33 miles per gallon on average. The cost of gas is $2.95 per gallon where she lives. If she drives 363 miles i

kkurt [141]

$32.45..................

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3 years ago

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The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 44,663 miles, with a standard

expeople1 [14]

Answer:

The probability is $P(| \= X- \mu| < 199 ) = 0.733$

Step-by-step explanation:

From the question we are told that

The mean mileage of a tire is $\mu = 44663$

The standard deviation is $\sigma = 2594$

The sample size is n = 209

Generally the standard error of mean is mathematically represented as

$\sigma_{x} = \frac{\sigma}{\sqrt{n} }$

=> $\sigma_{x} = \frac{2594}{\sqrt{209} }$

=> $\sigma_{x} = 179.4$

Generally the probability that the sample mean would differ from the population mean by less than 199 miles is mathematically represented as

$P(| \= X- \mu| < 199 ) = P(|\frac{\= X - \mu}{ \sigma_{x}}| < \frac{199}{ 179.4})$

$\frac{\= X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ \= X )$

=> $P(| \= X- \mu| < 199 ) = P(|Z| < \frac{199}{ 179.4})$

=> $P(| \= X- \mu| < 199 ) = P(|Z|< 1.11)$

=> $P(| \= X- \mu| < 199 ) = P(-1.11 \le Z \le 1.11 )$

=> $P(| \= X- \mu| < 199 ) = P(Z \le 1.11 ) - P( Z \le -1.11 )$

From the z table the area under the normal curve to the left corresponding to 1.11 and -1.11 is

$P(Z \le 1.11 ) = 0.8665$

and

$P(Z \le - 1.11 ) = 0.1335$

So

$P(| \= X- \mu| < 199 ) = 0.8665 - 0.1335$

=> $P(| \= X- \mu| < 199 ) = 0.733$

8 0

3 years ago

Given the system below:

Gwar [14]

E is the correct option to choose

6 0

4 years ago

What values of a and b make the equation true? StartRoot 648 EndRoot = StartRoot 2 Superscript a Baseline times 3 Superscript b

kramer

Option C: $a=3, b=4$ is the value of a and b

Explanation:

Given that the expression $\sqrt{648}=\sqrt{2^a\times3^b}$

We need to determine the value of a and b

Let us consider the term $\sqrt{648}$ and take the prime factorization of the term 648

Thus, we have,

648 divides by 2,

$648=2 \cdot 324$

324 divides by 2,

$648=2 \cdot 2 \cdot 162$

162 divides by 2,

$648=2 \cdot 2 \cdot 2 \cdot 81$

81 divides by 3,

$648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 27$

27 divides by 3,

$648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 3 \cdot 9$

9 divides by 3,

$648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 3 \cdot 3 \cdot 3$

Thus, we have,

$\sqrt{648}=\sqrt{2^{3} \cdot 3^{4}}$

Therefore, equating the powers of 2 and 3, we get,

$a=3, b=4$

Hence, the value of a and b is 3 and 4

Thus, Option C is the correct answer.

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3 years ago

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