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Mademuasel [1]
3 years ago
5

How do you work out: Ben and Sue shared £60 in the ratio 2:3. work out how much each person gets

Mathematics
1 answer:
Sedbober [7]3 years ago
4 0
(2/3)=0.66667=x/y
x+y=60
x=60-y
(60/y)-1=2/3
60/y=5/3
y=36
x+36=60
x=24

24:36
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Can you find the missing angles?
Nitella [24]
Every triangle has 180 degrees when you add there angles so you know that they will add up to 180
they are right triangles so the right angle has 90 degrees 
so for the yellow triangle 
90+45+x=180
135+x=180
45=x
we can tell where the purple and yellow triangle touch is 90 so 45+x=90 to find that angle which is 45
and the other one is 45 
so there are two 90 degree angles and three 45 degree angles.
I hope that made sence
5 0
3 years ago
Read 2 more answers
The triangle area is 90ft^2 and the height is 10 what's the base
Sidana [21]
Area of triangle = 1/2 x base x height
Let the base be "b"

90 = 1/2 x 10 x b
90 = 5b
b = 18 ft

Base = 18 ft
4 0
4 years ago
Given the function f(x)=(x-2)(x+3)(2x+3), which set includes all of the zeros for the polynomial?
Marrrta [24]

Answer:

{2, -3, -3/2}

Step-by-step explanation:

hi! we can set each of the binomials equal to 0 to find the zeros of this polynomial.

x-2=0

x=2

x+3=0

x=-3

2x+3=0

2x=-3

x=-3/2

5 0
3 years ago
PLEASE HELP!! Which describes the graph of y = (x + 7)^2 - 9?
mezya [45]

Answer:

The answer is D. Vertex at (-7,-9).

Step-by-step explanation:

The equation is in vertex form, so you take the opposite of x and the constant stays the same. So, the opposite of 7 is -7 and -9 stays the same.

5 0
3 years ago
Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is
Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since,  its head is twice as likely to occur as its tail.

p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n  = 3

p=\dfrac{2}{3}

q=\dfrac{1}{3}

Now,

P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111

Hence, a) 0.2222, b) 0.3292, c) 0.1111

8 0
3 years ago
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