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2 answers:
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Remember pemdas
simpliify pathentsees, exponents then multiply divide add subtract
some exponential laws
![(xyz)^m=[(x)^m][(y)^m][(z)^m]](https://tex.z-dn.net/?f=%28xyz%29%5Em%3D%5B%28x%29%5Em%5D%5B%28y%29%5Em%5D%5B%28z%29%5Em%5D)
we have
(-5m^2q)^2(-3m^3q)
do each seperately
(-5m^2q)^2=
[(-5)^2][(m^2)^2][(q)^2]=
[25][m^4][q^2]=
25m^4q^2
second part
(-3m^3q)^3=
[(-3)^3][(m^3)^3][(q)^3]=
[-27][m^9][q^3]=
-27m^9q^3
so we multiply them together
(25m^4q^2)(-27m^9q^3)=
(25)(m^4)(q^2)(-27)(m^9)(q^3)=
(25)(-27)(m^4)(m^9)(q^2)(q^3)=
(-675)(m^13)(q^5)=
-675m^13q^5
answer is first one
simpliify pathentsees, exponents then multiply divide add subtract
some exponential laws
we have
(-5m^2q)^2(-3m^3q)
do each seperately
(-5m^2q)^2=
[(-5)^2][(m^2)^2][(q)^2]=
[25][m^4][q^2]=
25m^4q^2
second part
(-3m^3q)^3=
[(-3)^3][(m^3)^3][(q)^3]=
[-27][m^9][q^3]=
-27m^9q^3
so we multiply them together
(25m^4q^2)(-27m^9q^3)=
(25)(m^4)(q^2)(-27)(m^9)(q^3)=
(25)(-27)(m^4)(m^9)(q^2)(q^3)=
(-675)(m^13)(q^5)=
-675m^13q^5
answer is first one