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igomit [66]
3 years ago
11

What adds up to -54 and multiplies to -16

Mathematics
1 answer:
Kaylis [27]3 years ago
8 0
X + y = -54
xy = -16

xy = -16
\frac{xy}{x} = \frac[-16}{x}
y = \frac{-16}{x}

x + y = -54
x + \frac{-16}{x} = -54
\frac{x^{2}}{x} + \frac{-16}{x} = -54
\frac{x^{2} - 16}{x} = -54
x^{2} - 16 = -54x
x^{2} + 54x - 16 = 0
x = \frac{-(54) \± \sqrt{(54)^{2} - 4(1)(-16)}}{2(1)}
x = \frac{-54 \± \sqrt{2916 + 64}}{2}
x = \frac{-54 \± \sqrt{2980}}{2}
x = \frac{-54 \± 59.6}{2}
x = -27 \± 29.8
x = -27 + 29.8    or    x = -27 - 29.8
x = 2.8    or    x = 56.8

     x + y = -54
  2.8 + y = -54
- 2.8          - 2.8
           y = -56.8
     (x, y) = (2.8, -56.8)

             or

        x + y = -54
  -56.8 + y = -54
+ 56.8        + 56.8
              y = 2.8
        (x, y) = (-56.8, 2.8)

The two numbers that add up to -54 and multiply to -16 are -56.8 and 2.8.
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Step-by-step explanation:

6 episodes in 1.5 hrs.

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3 years ago
Use properties of addition and subtraction to evaluate the expression <br> -42 - 29 - 28
Setler [38]
(-42) (-29) (-28)
-42 - 29 = -71
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hope this helps
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What is the measure of f in the figure shown?
SCORPION-xisa [38]

Answer:

The measure of angle f is 61°

Step-by-step explanation:

A straight line is 180° meaning;

180 - 98 = 82

82 is the angle measure of the unlabeled angle.

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37 + 82 = 119

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5 0
3 years ago
Graph the hyperbola using the transverse axis, vertices, and co-vertices:
Reptile [31]

See attachment for the graph of the hyperbola 12x^2 - 3y^2 - 108 = 0

<h3>How to graph the hyperbola?</h3>

The equation of the hyperbola is given as:

12x^2 - 3y^2 - 108 = 0

Start by calculating the transverse axis

So, we have:

<u>Transverse axis</u>

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

Where

a = 3 and b = 6

The transverse axis is calculated as:

y = ±b/a(x - h) + k

So, we have:

y = ±6/3(x - 0) + 0

Evaluate the difference and sum

y = ±6/3x

Evaluate the quotient

y = ±2x

This means that the transverse axes are y = 2x and y =-2x

<u>The vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

<u>The co-vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

And

a = 3 and b = 6

The co-vertices are

(h - a, k) and (h + a, k)

So, we have:

(0 - 3, 0) and (0 + 3, 0)

Evaluate

(-3,0) and (3, 0)

See attachment for the graph of the hyperbola

Read more about hyperbola at:

brainly.com/question/26250569

#SPJ1

4 0
1 year ago
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