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ivanzaharov [21]
3 years ago
14

Given (-3, 1) and (3,-3). The slope of the line is _______ . The equation of the line is ___________ .

Mathematics
2 answers:
agasfer [191]3 years ago
8 0

Answer:

-2/3

y= -2/3x-1

Step-by-step explanation:

Slope is found from

m = (y2-y1)/(x2-x1)

    = (-3-1)/(3--3)

    = -4/(3+3)

   = -4/6

   = -2/3

The equation of the line can be found by using point slope form

y-y1=m(x-x1)

y-1 = -2/3(x--3)

y-1 = -2/3(x+3)

Distribute the -2/3

y-1 = -2/3x -2

Add 1 to each side

y-1+1 = -2/3x-2+1

y = -2/3x-1

chubhunter [2.5K]3 years ago
3 0

Answer:

-2/3

y=-2/3 x -1

Step-by-step explanation:

To write the equation of a line we must have a slope and a point. To find the slope we use the slope formula and substitute (x,y) points in it as shown below:

m=\frac{y_2-y_1}{x_2-x_1}=\frac{-3-1}{3--3}=\frac{-4}{3+3}=\frac{-4}{6}=\frac{-2}{3}

Now that we have the slope, plug in the slope and choose one point to plug into the point slope formula. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.  

(y-1)=-2/3(x--3)  

y-1=-2/3(x+3)

y=-2/3 x -6/3 +1

y=-2/3 x -1


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we have

A(-2, 2),B(6, 2),C(0, 8)

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

P=AB+BC+AC

and

the area of the triangle is equal to

A=\frac{1}{2}*base *heigth

in this problem

base=AB\\heigth=DC

we know that

The distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Step 1

<u>Find the distance AB</u>

A(-2, 2),B(6, 2)

Substitute the values in the formula

d=\sqrt{(2-2)^{2}+(6+2)^{2}}

d=\sqrt{(0)^{2}+(8)^{2}}

dAB=8\ units

Step 2

<u>Find the distance BC</u>

B(6, 2),C(0, 8)

Substitute the values in the formula

d=\sqrt{(8-2)^{2}+(0-6)^{2}}

d=\sqrt{(6)^{2}+(-6)^{2}}

dBC=6\sqrt{2}\ units

Step 3

<u>Find the distance AC</u>

A(-2, 2),C(0, 8)

Substitute the values in the formula

d=\sqrt{(8-2)^{2}+(0+2)^{2}}

d=\sqrt{(6)^{2}+(2)^{2}}

dAC=2\sqrt{10}\ units

Step 4

<u>Find the distance DC</u>

D(0, 2),C(0, 8)

Substitute the values in the formula

d=\sqrt{(8-2)^{2}+(0-0)^{2}}

d=\sqrt{(6)^{2}+(0)^{2}}

dDC=6\ units

Step 5

<u>Find the perimeter of the triangle</u>

P=AB+BC+AC

substitute the values

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P=22.81\ units

therefore

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Step 6

<u>Find the area of the triangle</u>

A=\frac{1}{2}*base *heigth

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substitute the values

A=\frac{1}{2}*8*6

A=24\ units^{2}

therefore

the area of the triangle is 24\ units^{2}

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