Step-by-step explanation:
a geometric sequence means that every term is created by multiplying the previous term by a certain constant factor. this factor is called the "common ratio".
so,
6×r = 18
r = 18/6 = 3
and a quick check tells us this works also for the next terms (18×3 = 54, 54×3 = 162), so it is indeed a geometric sequence with common ratio 3.
a0 = 6
a1 = a0 × 3 = 6×3 = 18
a2 = a1 × 3 = a0 × 3×3 = 6×3² = 54
an = a0 × 3^n = 6 × 3^n
so,
f(x) = 6×3^x, x is integer, x >=0
The values are 
and 
Explanation:
The expression is 
Simplifying, we get,
Since, both sides of the expression are equal, we can equate the corresponding values of A, B, C and D.
Thus, we get,
⇒ 
and 
Also, equating, 
, we get,
and
Thus, the values are and
Answer/Step-by-step explanation:
✔️Find AC using Pythagorean Theorem:
AC² = 25.2² - 11.3²
AC² = 507.35
AC = √507.35
AC = 22.5 (nearest tenth)
✔️Find m<A using trigonometric ratio:
Reference angle = A
Opp = 11.3
Hyp = 25.2
Sin(A) = opp/hyp
Sin(A) = 11.3/25.2
A = sin^{-1}(11.3/25.2)
A = 26.6° (nearest tenth)
✔️Find m<B using trigonometric ratio:
Reference angle = B
Adj = 11.3
Hyp = 25.2
Cos(A) = adj/hyp
Cos(A) = 11.3/25.2
A = cos^{-1}(11.3/25.2)
A = 63.4° (nearest tenth)
The midpoint, where the rest area is, will just be the average of the coordinates of Springfield and Columbus.
Rest Area=((1+7)/2, (-4+1)/2)
Rest Area=(4, -1.5)
The distance between the two cities can be found using the Pythagorean Theorem, which used in the manner is often referred to as the "distance" formula between two points.
d^2=(x2-x1)^2+(y2-y1)
d^2=(7-1)^2+(1--4)^2
d^2=36+25
d^2=61
d=√61 and we are told that each unit is equal to 5.38mi so the distance from Springfield to Columbus is:
D=5.38√61 mi
D≈42.02mi (to nearest hundredth of a mile)
Answer:
1,800
Step-by-step explanation:
