So,
123/20 is over 1. The denominator is 20, so what I would do is find out how many <em>whole </em>20's would fit in 123.
The result is that 6 20's would fit in 123 with 3 left over.
The answer is six and three-twentieths (6 3/20). It's already in simplest form.
From the given statement the unknown number is found to be - 1
The given statements can written in algebraic form as follows;
the unknown number = x
the number is multiplied by 6 = 6x
four less than twice the same number = 2x - 4
then, from the given statement the final equation equation becomes;
6x = 2x - 4
This unknown number can be solved by collecting similar terms together;
6x - 2x = -4
4x = -4
divide through by 4
![\frac{4x}{4} = \frac{-4}{4} \\\\x = -1](https://tex.z-dn.net/?f=%5Cfrac%7B4x%7D%7B4%7D%20%3D%20%5Cfrac%7B-4%7D%7B4%7D%20%5C%5C%5C%5Cx%20%3D%20-1)
Thus, the unknown number is - 1
Learn more here: brainly.com/question/24369824
Answer:
Multiply both sides of the equation by -2
Distribute -1/2 over (x+4)
Step-by-step explanation:
we have
![-\frac{1}{2}(x+4)=6](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D%28x%2B4%29%3D6)
<em>Method 1</em>
Multiply both sides of the equation by -2 ------> <em>Step 1</em>
![(x+4)=6*(-2)](https://tex.z-dn.net/?f=%28x%2B4%29%3D6%2A%28-2%29)
![(x+4)=-12](https://tex.z-dn.net/?f=%28x%2B4%29%3D-12)
Subtract 4 from both sides of the equation
![x=-12-4=-16](https://tex.z-dn.net/?f=x%3D-12-4%3D-16)
<em>Method 2</em>
Distribute -1/2 over (x+4)-------> <em>Step 1</em>
![-\frac{1}{2}x-2=6](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7Dx-2%3D6)
Multiply both sides of the equation by -2
![x+4=6(-2)](https://tex.z-dn.net/?f=x%2B4%3D6%28-2%29)
![x+4=-12](https://tex.z-dn.net/?f=x%2B4%3D-12)
Subtract 4 from both sides of the equation
![x=-12-4=-16](https://tex.z-dn.net/?f=x%3D-12-4%3D-16)
Answer:
Step-by-step explanation:
Given that at a party there are at least two people.
We have to prove that there are two people who know the same number of other people there
Let n>2 be the no of people there
If possible let us assume each person knows different number of persons
The number of persons any one knows can vary from 0 to n-1
Hence these n people will have 0,1,2....n-1 persons known.
Consider the last person who knows n-1 people this means that he knows everyone in the party. So there cannot be any one who does not know any one or with known persons number as 0.
Thus we get a contradiction.
So there must be atleast two people who know the same number of people