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<h3>Hope it is helpful....</h3>
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im pretty sure that it is -48 there is a chance im wrong
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<u>Answer:</u>
Cost of package of paper = 4$
Cost of stapler = 7$
<u>Explanation:</u>
Consider the cost of package of paper = x and that of stapler = y.
Now, we are given that cost of 3 paper packages and 4 staplers = 40$
Hence we get, 3x + 4y = 40 as 1st equation.
we are also given, cost of 5 paper packages and 6 staplers = 62$
Hence, the second equation is 5x + 6y = 62
Now, solving the two equations by method of elimination, we first equate coefficients of any one variable say x by multiplying 1st equation by 5 and second by 3 we get ->
15x + 20y = 200
15x + 18y= 186
Subtracting the two we get y = 7 and substituting this value of y in first equation we get x = 4
which gives the required cost of one paper package = x = 4$
and one stapler = y = 7$
