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hjlf
3 years ago
5

CAN SOMEONE PLEASE HELP I NEED THIS IN BY 11:59 PLEASE IM GUVING BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
scoray [572]3 years ago
5 0
Elise did the problem wrong. She needed to find out the kids surveyed total. Her answer was a smaller number than the number of kids that liked math the most.

i’m not so good at explaining things :/
hope this helps a little!!
ludmilkaskok [199]3 years ago
5 0

Error Analysis:

The mistake Elise of multiplying the revealed part (over whole) by the percentage given. She calculated 25% of the math students surveyed rather than finding the students in whole.

Correct Work:

20 students / .25 = 80 students surveyed

Or

20 students * 4 = 80 students surveyed.

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NEED HELP In 5 OR MORE SENTENCES, write a short story explaining the graph OR write about the key features of the graph.
posledela

A short story that explains the graph is a man riding a sport car.

  • He spent a total time of 60 s.
  • He initial distance covered (50 m) at a speed of 2 m/s (rate of change in <em>section A</em>) before making a stop <em>(section B).</em>
  • He then covered another distance (30 m) at a speed of 3 m/s (rate of change in <em>section C</em>) before finally stopping.
  • In a total of 60 s, he traveled a total distance of 80 m.

A short story that can be written for the graph is a story of a man riding a sport car. He made a stop then continued later.

<em>Section A </em>shows the time spent and distance traveled from his the start position to when he stopped at first.

<em>Section B </em>shows the time spent when he first stopped.

<em>Section C </em>shows the time and distance traveled before arriving at his final destination.

The following are some details and key features of the graph:

<em><u>1. The </u></em><em><u>rate of change</u></em><em><u> in each section:</u></em>

Section A rate of change = rise/run = \frac{50 - 0}{25 - 0} = \frac{50}{25} = 2 $ m/s

Section B rate of change = rise/run =\frac{50 - 50}{60 - 25} = \frac{0}{35} = 0 $ m/s

Section C rate of change = rise/run =\frac{80 - 50}{70 - 60} = \frac{30}{10} = 3 $ m/s

The rate of change here represents the speed at which he drove.

<em><u>2. The </u></em><em><u>distance traveled</u></em><em><u> in each section:</u></em>

Distance traveled in Section A = 50 - 0 = 50 m

Distance traveled in Section B = 50 - 50 = 0 m

Distance traveled in Section C = 80 - 50 = 30 m

<em><u>3. The </u></em><em><u>total distance traveled:</u></em>

Total distance = 50 + 0 + 30 = 80 m

<em><u>4. The </u></em><em><u>total time spent </u></em><em><u>traveling:</u></em>

Total time spent = 70 - 0 = 60 s

In summary, a short story that explains the graph is a man riding a sport car.

  • He spent a total time of 60 s.
  • He initial distance covered (50 m) at a speed of 2 m/s (rate of change in <em>section A</em>) before making a stop <em>(section B).</em>
  • He then covered another distance (30 m) at a speed of 3 m/s (rate of change in <em>section C</em>) before finally stopping.
  • In a total of 60 s, he traveled a total distance of 80 m.

Learn more here:

brainly.com/question/24654519

4 0
3 years ago
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