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Mars2501 [29]
3 years ago
15

Help please I'm stuck show and explain your work

Mathematics
1 answer:
Deffense [45]3 years ago
7 0

The expressions D, E, and F represent a correct solution to the equation.

Step-by-step explanation:

Step 1:

First, we need to solve the given equation and find the value of x which satisfies the equation.

6(x+4)=20, (x+4) = \frac{20}{6}   = 3.333,

x = 3.333 - 4 = -0.666.

So the value of x for the given equation is -0.666.

Step 2:

Now we evaluate the values of the six given options to see which ones have an x value of -0.666.

A. \frac{20-4}{6}= \frac{16}{6}  = 2.666,

B. \frac{1}{6} (20-4)= \frac{1}{6} (16)=\frac{16}{6} = 2.666,

C. 20 -6 -4 = 20 - 10 = 10.

D. \frac{20}{6} -4= 3.333 - 4 = -0.666,

E. \frac{1}{6} (20-24) = \frac{1}{6} (-4)= -0.666,

F. (20-24)\frac{1}{6} = (-4)\frac{1}{6} = -0.666.

So the options D, E, and F represent a correct solution to the given equation.

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Answer:

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Step-by-step explanation:

Assume your diagram is like the one below.

The intersecting secant angles theorem states, "When two secants intersect outside a circle, the measure of the angle formed is one-half the difference between the far and the near arcs."

For your diagram, that means

\begin{array}{rcl}m\angle L &=&\dfrac{1}{2} \left(m \widehat {JM} - m\widehat {PQ}\right)\\\\(3x + 13)^{\circ}& = &\dfrac{1}{2} \left[(8x + 48)^{\circ} - (5x - 20)^{\circ}\right]\\\\3x + 13& = &\dfrac{1}{2}(8x + 48 - 5x + 20)\\\\3x + 13& = &\dfrac{1}{2}(3x + 68)\\\\6x + 26 & = & 3x + 68\\6x & = & 3x + 42\\3x & = & 42\\x & = & \mathbf{14}\\\end{array}

Check:

\begin{array}{rcl}(3\times14 + 13) & = &\dfrac{1}{2} \left[(8\times14 + 48)^{\circ} - (5\times14 - 20)^{\circ}\right]\\\\42 + 13& = &\dfrac{1}{2}(112 + 48 - 70 + 20)\\\\55& = &\dfrac{1}{2}(110)\\\\55 & = & 55\\\end{array}

It checks.

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