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Snezhnost [94]
3 years ago
8

Simplify. rewrite the expression in the form 9^n: 9^-3/9^12

Mathematics
1 answer:
sashaice [31]3 years ago
3 0

Answer:

9 ^ (-15)

Step-by-step explanation:

9^-3/9^12

We know that a^b/ a^c = a^(b-c)

9^-3/9^12 = 9 ^(-3-12)

                  =9^(-15)

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Miya flips a coin and rolls a 6-sided number cube labled 1-6 and records tge outcome. About how many times is she likely to flip
neonofarm [45]

Answer:

4 times

Step-by-step explanation:

Sample space :

6 sided cube = (1, 2, 3, 4, 5, 6)

Coin = (H, T)

Probability = required outcome / Total possible outcomes

Probability of head (H) = P(H) = 1 /2 = 0.5

Probability of 3 = P(3) = 1 /6 = 0.166666

Probability of heads and 3 on a single try = p(H) * p(3) = 0.5 * 0.166666 = 0.083333

Hence, expected number of times this is likely to occur in 48 tries :

0.083333 * 48 = 4

4 0
3 years ago
If 4C + 3 = 15, what is the value of C?
Soloha48 [4]
4c+3=15
You need to get rid of the 3
So you minus it from each side so you
4c=12
12/4=3
So c =3
4 0
3 years ago
Read 2 more answers
Determine which function has the greatest rate of change over the interval [0, 2].
ruslelena [56]
Remember that the average rate of change of a function over an interval is the slope of the straight line connecting the end points of the interval. To find those slopes, we are going to use the slope formula: m= \frac{y_{2}-y_{1}}{x_2-x_1}

Rate of change of a:
From the graph we can infer that the end points are (0,1) and (2,4). So lets use our slope formula to find the rate of change of a:
m= \frac{y_{2}-y_{1}}{x_2-x_1}
m= \frac{4-1}{2-0}
m= \frac{3}{2}
m=1.5
The average rate of change of the function a over the interval [0,2] is 1.5

Rate of change of b:
Here the end points are (0,0) and (2,2)
m= \frac{2-0}{2-0}
m= \frac{2}{2}
m=1
The average rate of change of the function b over the interval [0,2] is 1

Rate of change of c:
Here the end points are (0,-1) and (2,0)
m= \frac{0-(-1)}{2-0}
m= \frac{1}{2}
m=0.5
The average rate of change of the function c over the interval [0,2] is 0.5

Rate of change of d:
Here the end points are (0,0.5) and (2,2.5)
m= \frac{2.5-0.5}{2-0}
m= \frac{2}{2}
m=1
The average rate of change of the function d over the interval [0,2] is 1

We can conclude that the <span>function that has the greatest rate of change over the interval [0, 2] is the function a.</span>
4 0
3 years ago
Use multiplication to solve the proportion.<br><br> y/9 = 44/54
QveST [7]
9•44=396
396/54=7.3 repeating
Therefore y=7.33
3 0
3 years ago
Read 2 more answers
A line that is parallel to the graph of y=1/2+6 with a y-intercept of(0,-2)
Elena L [17]
1/2x-2 is one answer
5 0
3 years ago
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