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mash [69]
2 years ago
9

Which expression is equivalent to StartFraction c squared minus 4 Over c + 3 EndFraction divided by StartFraction c + 2 Over 3 (

c squared minus 9) EndFraction
Mathematics
2 answers:
-Dominant- [34]2 years ago
5 0

The options have not been given but three correct alternatives have been presented as the solution.

Answer:

3(c-2)(c-3) or3(c^2-5c+6) or 3c^2 - 15c + 18

Step-by-step explanation:

\dfrac{c^2-4}{c+3}\div\dfrac{c+2}{3(c^2-9)}

Applying the rule a^2 - b^2 = (a+b)(a-b) to the numerator of the first term and the denominator of the second term,

\dfrac{c^2-2^2}{c+3}\div\dfrac{c+2}{3(c^2-3^2)}

\dfrac{(c+2)(c-2)}{c+3}\div\dfrac{c+2}{3(c+3)(c-3)}

By changing ÷ to ×, we invert the second term

\dfrac{(c+2)(c-2)}{c+3}\times\dfrac{3(c+3)(c-3)}{c+2}

(c-2)\times3(c-3)

3(c-2)(c-3) = 3(c^2-5c+6) = 3c^2 - 15c + 18

Yakvenalex [24]2 years ago
4 0

Answer:

The answer is C on edge

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Helen is putting a fence around her flower garden, which is in the shape of half of a circle and a rectangle. If the semicircle
erastova [34]

Answer:

Part 1) Helen will need 38 feet of fencing

Part 2) The perimeter around the three sides of the rectangular section of the garden is 27 feet

Part 3) The approximate distance around half of the circle is 11 feet

Step-by-step explanation:

Part 1) How much fencing will Helen need?

Find out the perimeter

we know that

The perimeter of the figure is equal to the sum of three sides of the rectangular section plus the circumference of a semicircle

so

P=2L+W+\frac{1}{2}\pi D

we have

L=10\ ft\\W=7\ ft\\D=7\ ft\\\pi =\frac{22}{7}

substitute

P=2(10)+7+\frac{1}{2}(\frac{22}{7})(7)

P=20)+7+11=38\ ft

therefore

Helen will need 38 feet of fencing

Part 2)  What is the perimeter around the three sides of the rectangular section of the garden?

P=2L+W

we have

L=10\ ft\\W=7\ ft

substitute

P=2(10)+7

P=20+7=27\ ft

therefore

The perimeter around the three sides of the rectangular section of the garden is 27 feet

Part 3) What is the approximate distance around half of the circle?

Find the circumference of semicircle

C=\frac{1}{2}\pi D

we have

D=7\ ft\\\pi =\frac{22}{7}

substitute

C=\frac{1}{2}(\frac{22}{7})(7)

C=11\ ft

therefore

The approximate distance around half of the circle is 11 feet

4 0
2 years ago
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A rectangle has a length of 42 inches and a width of 14 inches. Which of the following is not equal to the ratio of the rectangl
Temka [501]
The ratio of the rectangle's length to its width is 42/14 which simplifies to 3/1 by factoring out 14 out of the numerator and denominator.
Any ratio that is not 3:1, or a multiple of 3:1, is not equal.

List of Equal Ratios: 6:2, 9:3, 12:4, etc.
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lesantik [10]
The value of x is 30; hence 4x is equal to 120. That is because the sum of the angles of a triangle is 180. So, add x, x and 4x together, you get 6x. Divide 180 by 6, you get 30. Hope this helped!
7 0
3 years ago
What is the midpoint of the line segment with endpoints (-2,-2) and (4.6)?
erma4kov [3.2K]

Answer:

Step-by-step explanation:

(-2,2) ...x1 = -2 and y1 = 2

(4,6)..x2 = 4 and y2 = 6

midpoint formula :

m = ((x1 + x2) / 2 , (y1 + y2) / 2)

m = ((-2 + 4) / 2 , (2 + 6) / 2)

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m = (1,4) <===

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A weight of 270 pounds falls
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Answer:

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Step-by-step explanation:

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