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padilas [110]
3 years ago
10

What is the equation of the parabola, in vertex form, with vertex at (2,-4) and

Mathematics
2 answers:
kari74 [83]3 years ago
8 0

Answer:

y=\left(x-2\right)^{2}-4

Step-by-step explanation:

I graphed the vertex and directrix on the graph below and found the equation for the parabola.

If this answer is correct, please make me Brainliest!

Ad libitum [116K]3 years ago
4 0

Answer:

I'm not good at math but you can add me on Instagram npw.angela

Step-by-step explanation:

i need new friends

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Matt gets paid an hourly rate of $12.50 for the first 40 hours he works in a week. After 40 hours , Matt gets paid at an overtim
lukranit [14]

12.50 x 40 = 500; this is his first week pay from $12.50 an hour for 40 hours  

(15 x 55) + 100 = 925; this is the second pay from $15 an hour for 55 hours and an additional $100


Hope this helps! (If not correct me if its wrong xd)

5 0
3 years ago
Determine if 9 is rational or irrational and give a reason for your answer.
Irina18 [472]

Answer:

9 is an rational number because it is a whole number

Step-by-step explanation:

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3 years ago
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Andreas93 [3]

Step-by-step explanation:

multiply length, width, and height

6x4x6 and 7x4x6

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Second line: <u>168cm</u>

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4 0
2 years ago
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stacy's thermostat is set at 74°F.Which range of numbers contains the opposite of stacy's thermostat setting?
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8 0
3 years ago
Which series of transformations will not map figure H onto itself
7nadin3 [17]

Answer:

D

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation (x+0,y-2) will map vertices of the square into points

  • (2,1)\rightarrow (2,-1);
  • (1,2)\rightarrow (1,0);
  • (2,3)\rightarrow (2,1);
  • (3,2)\rightarrow (3,0).

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

  • (2,-1)\rightarrow (2,3);
  • (1,0)\rightarrow (1,2);
  • (2,1)\rightarrow (2,1);
  • (3,0)\rightarrow (3,2)

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation (x+2,y-0) will map vertices of the square into points

  • (2,1)\rightarrow (4,1);
  • (1,2)\rightarrow (3,2);
  • (2,3)\rightarrow (4,3);
  • (3,2)\rightarrow (5,2).

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

  • (4,1)\rightarrow (2,1);
  • (3,2)\rightarrow (3,2);
  • (4,3)\rightarrow (2,3);
  • (5,2)\rightarrow (1,2)

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation (x+3,y+3) will map vertices of the square into points

  • (2,1)\rightarrow (5,4);
  • (1,2)\rightarrow (4,5);
  • (2,3)\rightarrow (5,6);
  • (3,2)\rightarrow (6,5).

2nd transformation = reflection over y = -x + 7 will map vertices into points

  • (5,4)\rightarrow (3,2);
  • (4,5)\rightarrow (2,3);
  • (5,6)\rightarrow (1,2);
  • (6,5)\rightarrow (2,1)

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation (x-3,y-3) will map vertices of the square into points

  • (2,1)\rightarrow (-1,-2);
  • (1,2)\rightarrow (-2,-1);
  • (2,3)\rightarrow (-1,0);
  • (3,2)\rightarrow (0,-1).

2nd transformation = reflection over y = -x + 2 will map vertices into points

  • (-1,-2)\rightarrow (4,3);
  • (-2,-1)\rightarrow (3,4);
  • (-1,0)\rightarrow (2,3);
  • (0,-1)\rightarrow (3,2)

These points are not the vertices of the initial square.

5 0
3 years ago
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