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DochEvi [55]
3 years ago
7

A recipe for sparkling grape juice calls for 1 1/2 quarts of sparkling water 3/4 quart of grape juice. Q1: How much sparkling wa

ter would you need to mix with 9 quarts juice? Q2: How much grape jucie would you need to mix 15/4 quarts of sparkling water ? Q3: How much of each ingredient would you need to make 100 quarts of punch?
Mathematics
1 answer:
kogti [31]3 years ago
3 0

Answer:

1) 18 Quart of Sparkling water need to mix with 9 quart grape juice

2) 15/2  Quart of grape juice required for 15/4 quarts of sparkling water.

3) Quantity of grape juice  and  sparkling water in 100 quart of punch are 33 1/3 quart  and 66 2/3 quart respectively.

Step-by-step explanation:

1 1/2 quarts = 1 + (1/2) = 3/2 quarts

1)  water required for 3/4 quart of grape juice =  3/2 quarts

so water required for 1 quart of grape juice = (3/2) ÷ (3/4) = (3/2)× (4/3) = 2 quarts

so water required for 9 quart of grape juice = 9 * 2 = 18 quart

18 Quart of Sparkling water need to mix with 9 quart grape juice

2) From solution of 1 ,

   For 18 quart of Sparkling water , grape juice require = 9 quart

   So for 1 quart of Sparkling water , grape juice require = 9÷18 = 1/2 Quart

   so for 15/4 quart of Sparkling water ,  grape juice require = 1/2 × 15/4 =

15/2  Quart of grape juice required for 15/4 quarts of sparkling water.

3)

in 1 we calculated that 18 Quart of Sparkling water need to mix with 9 quart grape juice that is 2 quart of Sparkling water need to mix with 1 quart of grape juice.

In other words 1 quart of grape juice + 2 quart of sparkling water is 3 quart of punch.

Quantity of Grape juice in 3 quart of punch = 1 quart

so quantity of grape juice in 1 quart of punch = 1/3 quart

And quantity of grape juice in 100 quart of punch = 100×(1/3) = 100/3 =

33 1/3

Quantity of sparkling water in 3 quart of punch = 2 quart

so quantity of sparkling water  in 1 quart of punch = 2/3 quart

And quantity of sparkling water  in 100 quart of punch = 100 ×2/3 quart = 66 2/3


 


     


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Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

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Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

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P(X

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(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

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Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

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Thus, the expected value of the temperature increase is 17.5°C.

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