$\dfrac{2m}{5}+3=7(4m-3)\ \ \ \ |use\ distributive\ property:a(b-c)=ab-ac\\\\\dfrac{2m}{5}+3=28m-21\ \ \ \ \ |multiply\ both\ sides\ by\ 5\\\\2m+15=140m-105\ \ \ \ |subtract\ 140m\ from\ both\ sides\\\\-138m+15=-105\ \ \ \ |subtract\ 15\ from\ both\ sides\\\\-138m=-120\ \ \ \ |divide\ both\ sides\ by\ (-138)\\\\m=\dfrac{120:6}{138:6}\\\\\boxed{m=\frac{20}{23}}$

7 0

3 years ago

Help wanted and needed I’m not good at math

stealth61 [152]

Answer:

$- \frac{7}{8}$

Step-by-step explanation:

Line d slope is 8/7, therefore the perpendicular is -7/8

8 0

2 years ago

During a 5-day work week, pete was sick for 2 days .what fraction of the work week was he sick?

timofeeve [1]

I think the answer is 2/5

6 0

2 years ago

consider the function represented by the equation 16b = 4r - 12. write the equation in function notation, where b is the indepen

katovenus [111]

When you write a function in the form $y=f(x)$ , y is the dependent variable, and x is the independent variable.

So, if b is the independent variable, it means that we have to solve the expression for r.

To do so, we perform the following steps: start with

$16b = 4r - 12$

Add 12 to both sides

$16b+12 = 4r$

Divide both sides by 4:

$4b+3 = r$

So, we wrote the expression in the form $r = f(b) = 4b+3$ , which means that r is the dependent variable and b is the independent variable, as requested.

4 0

2 years ago

16-z=12 solve equation​

16-z=12 solve equation