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3 years ago

5

Change 2 hours and 36 mins to a mixed number

1 answer:

defon3 years ago

5 0

You know you have two hours which will be the whole number. Then you take 36min and put it over 60min (total number of min in an hour) and you simplify by 6 to get 6/10 which can be simplified again to 3/5 so your final mixed number is
2 and 3/5 hours

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Artemon [7]

Answer:

Okay

Step-by-step explanation:

3 0

2 years ago

Solve using elimination<br><br> 2x+5y=34<br> x+2y=14

Darina [25.2K]

2x + 5y = 34

x+2y = 14

Multiply the second equation by two to create like terms for one variable.

2(x+2y = 14)

2x + 4y = 28

2x + 5y = 34

2x + 4y = 28 -- Subtract.

y = 34.28 = 6

Solve for x

x + 2(6) = 14

x + 12 = 14

x = 2

Check:

2 + 2(6) = 14

2 + 12 = 14

14 = 14

Answer:

X = 2

Y = 6

8 0

3 years ago

472 + 278 + 694 + 73 + 217 =<br>O 1,734<br>1,824<br>O 1,714<br>O 1,634

hichkok12 [17]

Answer:

1734

Step-by-step explanation:

add them

4 0

3 years ago

Read 2 more answers

Consider the diagram below. which of the following represents the values x,y and z?

Gemiola [76]

Answer:

$x=4\sqrt{6}\ units$

$y=4\sqrt{2}\ units$

$z=4\sqrt{3}\ units$

Step-by-step explanation:

The picture of the question in the attached figure

step 1

In the right triangle ABD

Applying the Pythagorean Theorem

$x^2=y^2+(12-4)^2$

$x^2=y^2+64$

$y^2=x^2-64$ ----> equation A

step 2

In the right triangle BDC

Applying the Pythagorean Theorem

$z^2=y^2+4^2$

$z^2=y^2+16$

$y^2=z^2-16$ ----> equation B

step 3

In the right triangle ABC

Applying the Pythagorean Theorem

$12^2=x^2+z^2$

$144=x^2+z^2$ ----> equation C

step 4

Equate equation A and equation B

$x^2-64=z^2-16$

$x^2=z^2+48$ -----> equation D

step 5

substitute equation D in equation C

$144=z^2+48+z^2$

solve for z

$2z^2=144-48$

$2z^2=96$

$z^2=48$

$z=\sqrt{48}\ units$

simplify

$z=4\sqrt{3}\ units$

Find the value of x

$x^2=z^2+48$

$x^2=48+48=96$

$x=\sqrt{96}\ units$

$x=4\sqrt{6}\ units$

Find the value of y

$y^2=z^2-16$

$y^2=48-16$

$y^2=32$

$y=\sqrt{32}\ units$

$y=4\sqrt{2}\ units$

3 0

2 years ago

Please HELP!! find the area of the rhombus.

balandron [24]

Answer:

32.5

Step-by-step explanation:

3 0

2 years ago