Answer:
part A: 72
part B=7
part C=7(5+9)
Step-by-step explanation:
A=the lowest common multiple found in both the 9 and 8 times table. 8s=8 16 24 32 40 48 56 64 72
9s=9 18 27 36 45 54 63 72
B=7 because 35=5×7 and if we break down 63,it
would be 9×7 or 3×3×7
C=7(5+9) because if we expand the brackets it would
be 7×5+7×9=35+63
Hope it helps?
9/10 equals 0.9 , 2/7 equals about 0.28 . So 0.9 - 0.28 = 0.62 if you need .62 in a fraction it's 31/50
The <em>complement </em>C'<em> </em>of some set C is essentially the set we get when we remove all of the elements of C from the universal set U.
Here, our universal set contains all of the numbers 1-16, and the set C contains all of the odd numbers between 1 and 16. If we were to put both of these sets in roster form:

If we remove all of the elements of C from the universal set U, we're left with the complement of C, which contains all of the <em>even numbers </em>between 1 and 16:

Answer:
d
Step-by-step explanation:
Answer: there is a relationship between study hours and test score. as the hours of studying increase, the test scores increase.