Question

If JL = 8x-3 and LK = 4x + 57, Find JK

Answer 1

JK =8x-3 +4X+57
JK = 12x+ 54

Answer 2

Answer: JK = 234

Concept:

Here, we need to know the idea of the segment addition postulate.

The Segment Addition Postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

Solve:

PART I: Find the value of x

Given information

JL = 8x - 3

LK = 4x + 57

Given expression deducted from the given figure

JL = LK

Substitute values into the expression

8x - 3 = 4x + 57

Add 3 on both sides

8x - 3 + 3 = 4x + 57 + 3

8x = 4x + 60

Subtract 4x on both sides

8x - 4x = 4x + 60 - 4x

4x = 60

Divide 4 on both sides

4x / 4 = 60 / 4

x = 15

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PART II: Find the value of JK

Given information

JL = 8x - 3

LK = 4x + 57

x = 15

Given expression deducted from the segment addition postulate

JK = JL + LK

Substitute values into the expression

JK = 8x - 3 + 4x + 57

JK = 8(15) - 3 + 4(15) + 57

Simplify by multiplication

JK = 120 - 3 + 60 + 57

Simplify by simple operation (addition/subtraction)

JK = 117 + 60 + 57

JK = 177 + 57

$\boxed{JK=234}$

Hope this helps!! :)

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