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Rama09 [41]
3 years ago
7

Robert needs to cut four shelves from a board that is 2.5 meters long. The second shelf is 18 centimeters longer than twice the

length of the first shelf. The third shelf is 12 centimeters shorter than the first shelf. The remaining shelf is 4 centimeters longer than the first shelf. If Robert must use the entire 2.5 meter board for the shelves, what is the length of the second shelf, in centimeters?
Mathematics
2 answers:
jeyben [28]3 years ago
8 0
I would say 640.5 centimeters. However, remember that this is high school work, and I am only in middle school. This may not be correct, as I am doubting myself, yet cannot find errors in my work. Please take caution with this answer! Hope this isn't a detriment to you, bye! :)
muminat3 years ago
6 0

Answer: waiiiit isnt it 114

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g The population of Little Townville in 2005 was 13,625 people. In 2009 the population grew to 15,325 people. Assume that this t
german

Answer:

a) P(t) = 11500 + 425t

b) The slope is of 425 people, which is by how much the population increases each year.

c) The vertical intercept is of 11500 people, and it represents the population of Little Townville in the year 2000.

d) 17,875 people.

Step-by-step explanation:

A linear function that measures population after t years has the following format:

P(t) = P(0) + at

In which P(0) is the vertical intercept, which represents the initial population, and a is the slope, which represents the yearly population.

a. Write a function for the population, P, in terms of the number of years since 2000.

The first step is finding the slope.

Finding the slope:

The slope is the change in the output divided by the change in the input, during a period of time.

The population of Little Townville in 2005 was 13,625 people. In 2009 the population grew to 15,325 people.

This means that in 2009 - 2005 = 4 years, the population increased by 15325 - 13625 = 1700.

So the slope is

a = \frac{1700}{4} = 425

So

P(t) = P(0) + 425t

Finding the initial population:

We want to find P(0), which is the population in 2000. The population of Little Townville in 2005 was 13,625 people, which means that P(5) = 13625. So

P(t) = P(0) + 425t

13625 = P(0) + 425*5

P(0) = 13625 - 425*5

P(0) = 11500

So

P(t) = 11500 + 425t

b. What is the slope of the function and what does it represent in the context of the problem. Include units.

The slope is of 425 people, which is by how much the population increases each year.

c. What is the vertical intercept of the function and what does it represent? Include units

The vertical intercept is of 11500 people, and it represents the population of Little Townville in the year 2000.

d. What do you believe the population was in 2015?

2015 is 2015 - 2000 = 15 years after 2000, so this is P(15).

P(15) = 11500 + 425*15 = 17875

17,875 people.

3 0
3 years ago
Assume that the heights of men are normally distributed. a random sample of 16 men have a mean height of 67.5 inches and a stand
sesenic [268]

Solution: The 99% confidence interval for the population standard deviation is given below:

\sqrt{\frac{(n-1)s^{2}}{chi^{2}_{\frac{\alpha}{2}}}}   \leqσ\leq \sqrt{\frac{(n-1)s^{2}}{chi^{2}_{1-\frac{\alpha}{2}}}}

\sqrt{\frac{15 (3.2)^{2}}{30.578}}\leqσ\leq \sqrt{\frac{15(3.2)^{2}}{4.601}}

2.2\leqσ\leq 5.8

6 0
3 years ago
Read 2 more answers
Quadrilateral JKLM is a parallelogram. What is the m kjn
artcher [175]

Answer:

solution: KL-2ML. LKIN=63x2=126*

Step-by-step explanation:

Mark me brainliest!!

4 0
2 years ago
What’s the equation if 2+6x=28 if x is 4
Yakvenalex [24]

Answer:

x = 4 is not a solution to the equation.

Step-by-step explanation:

2 + 6(4) = 28

2 + 24 = 28

26 =/= 28

3 0
3 years ago
[PLEASE ANSWER] Precalculus Question (has 2 parts)
artcher [175]
Part I

\bf \begin{array}{l|lllllll}
x&2&\boxed{4}&6&8&\boxed{10}&12&14\\\\
y&1&\boxed{6}&11&16&\boxed{21}&26&31
\end{array}\implies 
\begin{array}{llll}
(4,6)\\\\
(10,21)
\end{array}\\\\
-------------------------------\\\\

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 4}}\quad ,&{{ 6}})\quad 
%   (c,d)
&({{ 10}}\quad ,&{{ 21}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{21-6}{10-4}


part II

\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad 
\begin{array}{llll}
\textit{plug in the values for }
\begin{cases}
y_1=6\\
x_1=4\\
m=\boxed{?}
\end{cases}\\
\end{array}\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}


now, the form above is the point-slope form, and that'd be the equation, you can leave it like so, or you can solve for "y", and put it in slope-intercept, same equation though.
3 0
3 years ago
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