12] n is greater than or equal to -23
Answer:
ok so the probility of gettting one white fish is
13/23
and if we take out one white fish the problity is
12/22
so we just multiply
12/22*13/23=0.30830039525
so the problity is 0.30 if you choose two fish you will get white for both
Answer:
I actually do not know
Step-by-step explanation:
but I will try any which class I am 12
Answer:
M = 6
N= 7
Step-by-step explanation:
M + 7 = 3
M= 6
6 + 7 = 13, so we get 3 and carry 1
Now 1 + 4 + N = 12
1 + 4 + 7 = 12
So N = 7
Therefore,
46 + 77 = 123
Answer:
<h3>7/10</h3>
Step-by-step explanation:
Using set notation;
Let n(U) be the total number of students in the school = 100%
Let n(M) be the percentage of male students in the school = 56%
Let n(A) be the percentage of students between the ages of 18 and 20 (A) in the school = 32%
Let n(M∩A) be the percentage of both male and between the ages of 18 and 20 = 26%
The n(MUA)' be the number of female students in the school
Using the formula to get n(MUA)
n(MUA) = n(M)+n(A)- n(M∩A)
n(MUA) = 56+32-26
n(MUA) = 62%
Also, n(U) = n(MUA)+n(MUA)'
100 = 62+n(MUA)'
n(MUA)' = 100-62
n(MUA)' = 38%
This means that there are 38% of students in the school.
The probability of choosing a random student who is a female or between the ages of 18 and 20 is expressed as;
P(F or A) = P(F)+P(A) (mutually exclusive event i.e both cannot occur at the same time)
P(F or A) = 38/100 + 32/100
P(F or A) = (38+32)/100
P(F or A) = 70/100
P(F or A) = 7/10
Hence the probability of choosing a random student who is a female or between the ages of 18 and 20 is 7/10.