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Stels [109]
3 years ago
14

Help! how do you do q2?

Mathematics
1 answer:
sineoko [7]3 years ago
4 0
Negative is infinite
positive is dependent on whether or not a can = b etc.
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Arrange from least to greatest, 4.3, 5.5, 6 1/6, 15/4, 4 3/8?
Sophie [7]
Here are the numbers
4.3 , 5.5 , 6\frac{1}{6} , \frac{15}{4} , 4\frac{3}{8}
I'm going to change them into fractions
In the fractions, divide the numerator by the denominator
6\frac{1}{6}<em />⇔6.1666---
\frac{15}{4}⇔3.75
4 \frac{3}{8}⇔4.375
Now to arrange them from least to the greatest
\frac{15}{4} , 4.3 , 4 \frac{3}{8} , 5.5 , 6\frac{1}{6}
8 0
3 years ago
Read 2 more answers
Clare made $160 babysitting last summer. She put the money in a savings account that pays 3% interest per year. If clare doesn't
AVprozaik [17]

We have been given that Clare made $160 babysitting last summer. She put the money in a savings account that pays 3% interest per year. If Clare doesn't touch the money in her account, she can find the amount she'll have the next year by multiplying her current amount 1.03.

We are asked to write an expression for the amount of money Clare would have after 30 years if she never withdraws money from her account.

We will use exponential growth function to solve our given problem.

An exponential growth function is in form y=a(1+r)^x, where

y = Final value,

a = Initial value,

r = Growth rate in decimal form,

x = Time.

3\%=\frac{3}{100}=0.03

We can see that initial value is $160. Upon substituting our given values in above formula, we will get:

y=160(1+0.03)^x

y=160(1.03)^x

To find amount of money in Clare's account after 30 years, we need to substitute x=30 in our equation.

y=160(1.03)^{30}

Therefore, the expression 160(1.03)^{30} represents the amount of money that Clare would have after 30 years.

8 0
3 years ago
Functions.
never [62]

Answer:

2,5 and 6

Step-by-step explanation:

The answer is going to be option 2, 5 and 6 because the line touches -4,2 and 4 on the x axis. And these are the x values so that's why this is going to be the answer.

Hope this information helps you!

4 0
4 years ago
The amounts a soft drink machine is designed to dispense for each drink are normally​ distributed, with a mean of 11.711.7 fluid
dexar [7]

Answer:  0.1499

Step-by-step explanation:

Given : The amounts a soft drink machine is designed to dispense for each drink are normally​ distributed, with mean \mu=11.7\text{ fluid ounces}

Standard deviation : \sigma=0.2\text{ days}

z-score : z=\dfrac{X-\mu}{\sigma}

For X = 11.5  

z=\dfrac{11.5-11.7}{0.2}\approx-1

For X = 11.6  

z=\dfrac{11.6-11.7}{0.2}\approx-0.5

Now, the probability that the drink is between 11.511.5 and 11.611.6 fluid ounces will be :-

P(11.5

Hence, the probability that the drink is between 11.511.5 and 11.611.6 fluid ounces =0.1499

5 0
3 years ago
() = ()<br> ( + ) = () − <br> ( + ) = () − <br> () = () = <br> () =?
lubasha [3.4K]

Answer:

idk

Step-by-step explanation:

7 0
3 years ago
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