Answer:
cylinder
Step-by-step explanation:
The domain and inverse of the function
is
Domain =
,

What is a function?
A function from A to B is a rule that assigns to each element of A a unique element of B. A is called the domain of the function and B is called the codomain of the function.
There are different operations on functions like addition, subtraction, multiplication, division and composition of functions.
The given function is

r(x) is not defined if x - 4 = 0
r(x) is not defined for x = 4
Domain =
,
Where
is the set of all real number
Let r(x) = y

<em />
To learn more about function, refer to the link:
brainly.com/question/22340031
#SPJ4
Answer:
B) 75π cm³
Step-by-step explanation:
The volume of a cone is given by the formula ...
V = (1/3)πr²h
Your cone has r = 5 cm and h = 9 cm. Putting these values into the formula gives ...
V = (1/3)π(5 cm)²(9 cm) = 75π cm³
Answer:
4
Step-by-step explanation:
If two chords intersect externally, then the product of the length of the chord and the length of the part outside the circle is a constant.
Thus from the figure,
we can deduce that:
8×3=6×x
collecting the like terms together we get:
24=6x
x=4
Check the picture below.
so to find the surface area of the triangular prism, we simply add the areas of each of the figures composing it, as you can see is really just 2 triangles an 3 rectangles.
![\bf \stackrel{\textit{\Large Areas}}{\stackrel{triangles}{2\left[ \cfrac{1}{2}(4)(3) \right]}+\stackrel{\textit{rectangles}}{(3\cdot 10)+(4\cdot 10)+(5\cdot 10)}}\implies 12+30+40+50\implies 132](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7B%5CLarge%20Areas%7D%7D%7B%5Cstackrel%7Btriangles%7D%7B2%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%284%29%283%29%20%5Cright%5D%7D%2B%5Cstackrel%7B%5Ctextit%7Brectangles%7D%7D%7B%283%5Ccdot%2010%29%2B%284%5Ccdot%2010%29%2B%285%5Ccdot%2010%29%7D%7D%5Cimplies%2012%2B30%2B40%2B50%5Cimplies%20132)
now, to get the volume is simply the area of the triangular face times the length, well, we know the area of one of the triangles is 6, times 10 is just 6*10 = 60.