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Kipish [7]
3 years ago
14

How do you multiply these polynomials? 3xy^2(2y+4z)

Mathematics
1 answer:
nikitadnepr [17]3 years ago
7 0

Answer:

6xy^3 +12xy^2 z

Step-by-step explanation:

3xy^2 (2y+4z)

Multiply

3xy^2 * 2y + 3xy^2 *4z

common factors

3xy^3 +3xy^2 *4z

Multiply

6xy^3 +12xy^2 z

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You can transform 4x + 12=9x - 3 again into a simpler form by subtracting 4X from both sides to get 12=5x - 3. If you substitute
Ipatiy [6.2K]

Answer:

Yes. It is true.

Step-by-step explanation:

12= 5(3) -3

12=15-3

12=12 therefore, it is true

6 0
3 years ago
No one answer this I’ll mark you as 0
Dennis_Churaev [7]

Answer:

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5 0
3 years ago
A class is collecting aluminum cans. Every Monday each student brings in a bag with 10 cans. They put 10 bags into a box. How ma
yan [13]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
A retail outlet offers a retention bonus for each shopping season an employee remains with the company. Samuel's starting pay is
miv72 [106K]

Answer:

Samuel's hourly rate after n seasons with the company is f(n)= 12.50 + 0.35*n.  After 18 seasons with the company, Samuel's hourly rate will be 18.8 $ /hr.

Step-by-step explanation:

You know that Samuel's starting pay is $12.50/hr and for each season Samuel remains with the company, he receives a $0.35/hr raise.

Samuel's hourly rate after n seasons at the company will then be:

f(n)= 12.50 + 0.35*n

To determine the hourly rate after 18 seasons, you must replace the value n with 18:

f(18)= 12.50 + 0.35*18

Solving you get:

f(18)= 12.50 + 6.3

f(18)= 18.8

<u><em>Samuel's hourly rate after n seasons with the company is f(n)= 12.50 + 0.35*n.  After 18 seasons with the company, Samuel's hourly rate will be 18.8 $ /hr. </em></u>

6 0
3 years ago
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Answer:

your answer is D

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8 0
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