$\frac{3}{4} n = \frac{1}{2} \\ \\ multiply \: both \: sides \: by \: \frac{4}{3} \\ \\ \frac{ \cancel4}{\cancel3} \times \frac{\cancel3}{\cancel4} n = \frac{\cancel4 \: \: \red{ \bold2}}{3} \times \frac{1}{ \cancel2} \\ \\n = \frac{2 \times 1}{3 \times 1} \\ \\ n = \frac{2}{3}$

4 0

2 years ago

Read 2 more answers

I need to get the left side to equal the right side. Keeping the right side alone and not changing it.

likoan [24]

<u>To prove the trigonometric equation:</u>

$\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)$

$RHS=(\sin x+\cos x)(1-\sin x \cos x)$

We know that $\sin^2x +\cos^2x=1$ , substitute this in place of 1.

$=(\sin x+\cos x)(\sin^2x +\cos^2x-\sin x \cos x)$

Multiply each term of the first term with each term of the 2nd term.

$=\sin^3x + \sin x \cos^2x-\sin^2 x \cos x+\cos x \sin^2 x + \cos^3 x-\sin x\cos^2 x$

Group like terms together.

$=\sin^3x +( \sin x \cos^2x-\sin x\cos^2 x)+(\cos x \sin^2 x-\sin^2 x \cos x) + \cos^3 x$

$=\sin^3x +( 0)+(0) + \cos^3 x$

$=\sin^3x + \cos^3 x$

= LHS

RHS = LHS

$\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)$

Hence proved.

7 0

3 years ago

What property is illustrated by 6*1=6?

KatRina [158]

For this case we have the following expression:
6 * 1 = 6
We observe that we have two numbers that multiplied give as a result the value of one of the numbers.
The name of this property is called identity property.
In matrices there is also the identity matrix. It is a matrix whose diagonal is formed by the number one.
Answer:
A property that is illustrated by 6 * 1 = 6 is:
identity

5 0

3 years ago