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NISA [10]
3 years ago
15

A computer is sold for a certain price and then its value changes exponentially over time.

Mathematics
1 answer:
sineoko [7]3 years ago
7 0
the computer loses 50%, percent of its value each year. (Answer)
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alukav5142 [94]

Answer:

B

Step-by-step explanation:

The hight compared to the volume should be less hight but more volume

8 0
2 years ago
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A circle with radius of 3 cm sits inside a circle with radius of 5 cm. What is the area of the shaded region? Round your final a
DiKsa [7]

Hello!!

So first you need to find the area of the green circle. The formula for finding area for a circle is A = π r2. So the area for the green circle is 28.26 cm. Then you need to find the area of the blue circle. (Using the same formula) which would be 78.5. Then you subtract the value of the green circle to get the value of the shaded region which then your final answer is 50.24 cm. Hope this helped!!

8 0
3 years ago
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For each of the following wages, determine the Medicare tax that would be withheld. i. $23,660 ii. $89,000 iii. $166,090 a. i. $
sweet [91]

the answer is A Bois

7 0
3 years ago
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Enter the expression N0e−λt, where N0 is N-naught (an N with a subscript zero) and λ is the lowercase Greek letter lambda.
Natali5045456 [20]
So the question tells to express the expression in your problem where N0 is N-naught and the symbol represent the lower case Greek letter lambda. So the best answer or expression would be that the lambda is the wavelength of the expression. I hope you are satisfied with my answer 
7 0
3 years ago
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Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2a
Vitek1552 [10]

Answer:

2ab - 6a + 5b - 15

Step-by-step explanation:

Given

2ab - 6a + 5b + \_

Required

Fill in the gap to produce the product of linear expressions

2ab - 6a + 5b + \_

Split to 2

(2ab - 6a) + (5b + \_)

Factorize the first bracket

2a(b - 3) + (5b + \_)

Represent the _ with X

2a(b - 3) + (5b + X)

Factorize the second bracket

2a(b - 3) + 5(b + \frac{X}{5})

To result in a linear expression, then the following condition must be satisfied;

b - 3 = b + \frac{X}{5}

Subtract b from both sides

b - b- 3 = b - b+ \frac{X}{5}

- 3 = \frac{X}{5}

Multiply both sides by 5

- 3 * 5 = \frac{X}{5} * 5

X = -15

Substitute -15 for X in 2a(b - 3) + 5(b + \frac{X}{5})

2a(b - 3) + 5(b + \frac{-15}{5})

2a(b - 3) + 5(b - \frac{15}{5})

2a(b - 3) + 5(b - 3)

(2a + 5)(b - 3)

The two linear expressions are (2a+ 5) and (b - 3)

Their product will result in 2ab - 6a + 5b - 15

<em>Hence, the constant is -15</em>

3 0
3 years ago
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