Solve the equation. -9x + 1 = -x + 17 O x=-8 O x= -2 Ox=2 O x= 8

Martha wrote an example of a quadratic function for a homework assignment. The function she wrote is shown. f(x) = 5x3 + 2x2 + 7

Wittaler [7]

Answer:

The first term, 5x^3, can be eliminated.

The exponent on the first term, 5x^3, can be changed to a 2 and then combined with the second term, 2x^2

Step-by-step explanation:

The highest degree allowed in a quadratic function is 2, so the third degree term (the first term) needs to be eliminated or changed. The change shown above is one of many possibilities.

3 0

3 years ago

Choose the correct product of (6x − 2)(6x + 2). (1 point)

Vanyuwa [196]

You did not give any choices but this can easily be solved using the FOIL method.

FOIL stands for First, Outside, Inside, Last.

In your equation you have (6x-2)(6x+2)
You will multiply the terms that correspond to each letter

First: Means first terms of each set. In this case 6x and 6x
6x x 6x = $36x^{2}$ Now you have your first term in the sequence.

Outside: Means terms found in the outside areas of the whole equation, in this case it is 6x and 2
6x x 2 = 12x Now this is the second term

Inside: Means terms found in the inside areas of the whole equation, in this case it is -2 and 6x
-2 x 6x = -12x Now this is your third term

Last: Means the last terms of each set. In this case it is -2 and 2
-2 x 2 = -4 This is your last term

Now you have what you need for your new equation:

$36x^{2} + 12x -12x - 4$

Because your second and third terms are like terms, you can combine them by doing the operation indicated. 12x-12x = 0 so now you can cancel it out from your equation and your left with:

$36 x^{2} - 4$ This is your product

6 0

3 years ago

The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$