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Andrews [41]
4 years ago
9

Simplify the expression -9(x+11)

Mathematics
1 answer:
elena55 [62]4 years ago
6 0

Hi! What you need to use here is the distributive property:

-9( x + 11)

-9(x) + -9(11)

-9x + (-99)    or    -9x - 99

Hope this helps you! Happy Thanksgiving, here's a turkey!

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12

Step-by-step explanation:

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580 books were delivered to a warehouse and 29 were found to be damaged.
Anvisha [2.4K]

Answer:

I think it's would be 5%

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7 0
3 years ago
10) Solve the problem below using any method. Define your variables and write out the two
irga5000 [103]

Answer:

Variables: r, s

Number of Regular Tickets: 215

Equations: 8r + 6s = 3580; r + s = 525

Number of Senior Tickets: 310

Step-by-step explanation:

10) Solve the problem below using any method. Define your variables and write out the two equations. Then solve the problem.

A movie theater sells regular tickets for $8.00 and senior tickets for $6.00. One evening the theater

sold 525 tickets and took in $3580 in revenue. How many of each type of ticket were sold?

let r = number of regular tickets

let s = number of senior tickets

Equations:

The first equation deals with money.

8r + 6s = 3580

The second equation deals with numbers of tickets.

r + s = 525

Use the substitution method.

Solve the second equation for r.

r + s = 525

r = 525 - s

Substitute 525 - s for r in the first equation.

8r + 6s = 3580

8(525 - s) + 6s = 3580

4200 - 8s + 6s = 3580

4200 - 2s = 3580

-2s = -620

s = 310

Now substitute 310 for s in the equation r = 525 - s

r = 525 - 310

r = 215

Variables: r, s

Number of Regular Tickets: 215

Equations: 8r + 6s = 3580; r + s = 525

Number of Senior Tickets: 310

7 0
1 year ago
Solving Rational equations. LCD method. Show work. Image attached.
Dmitry [639]

Answer:

b=1

Step-by-step explanation:

The given rational equation is

\frac{2b-5}{b-2} -2=\frac{3}{b+2}

The Least Common Denominator is (b+2)(b-2).

Multiply each term in the equation by the LCD.

(b+2)(b-2)\times \frac{2b-5}{b-2} -(b+2)(b-2)\times2=(b+2)(b-2)\times\frac{3}{b+2}

Simplify;

(b+2)\times \frac{2b-5}{1} -2(b+2)(b-2)=(b-2)\times\frac{3}{1}

(b+2)(2b-5) -2(b+2)(b-2)=3(b-2)

Expand and group similar terms

2b^2-5b+4b-10 -2(b^2-4)=3b-6

2b^2-5b+4b-10 -2b^2+8=3b-6

-b-2=3b-6

3b+b=-2+6

4b=4

b=1

3 0
3 years ago
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