Angle 6 and angle 7 are examples of which type of angle pair?

E: 84:62 <br> help me please

vfiekz [6]

I pretty sure you times it by 3 and then you get 21:18

7 0

4 years ago

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Do you know how to find rate of change? X&Y intercepts? Zeros?

Rzqust [24]

#Rate of change

Rate of change is slope

If two points be (x1,y-1) and (X2,Y2) then

Slope=m=y_2-y_1/x_2-x_1

If a line be ax+by+c=0

m=-a/b

#X and y inetercept

If a equation given y=mx+b

To find x intercept put y=0
To find y inetercept put x=0

#Zeros

To find the zeros spot out the x inetercepts

The x values of the x intercepts are the zeros

3 0

3 years ago

You are trying to estimate the average amount a family spends on food during a year. In the past the standard deviation of the a

svetoff [14.1K]

Answer:

$n=(\frac{2.58(1000)}{50})^2 =2662.56 \approx 2663$

So the answer for this case would be n=2663 rounded up to the nearest integer

Step-by-step explanation:

We have the following info:

$ME = 50$ margin of error desired

$\sigma = 1000$ the standard deviation for this case

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =50 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 99% of confidence interval now can be founded using the normal distribution. The significance is $\alpha=0.01$ . And for this case would be $z_{\alpha/2}=2.58$ , replacing into formula (b) we got:

$n=(\frac{2.58(1000)}{50})^2 =2662.56 \approx 2663$

So the answer for this case would be n=2663 rounded up to the nearest integer

5 0

3 years ago

799.45 original price and 15%sale what is the final price

den301095 [7]

Steps:
1. Do a proportion
X/799.45 times 15/100
2. Do 15 times 799.45 which equals 11,991.75
3. Divide 11,991.75 by 100
4. 119. 91 is the price being taken off
5. Do 799.45 minus 119.91
6. Your answer is
$679.54

8 0

3 years ago

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Mathematical connection A lighthouse casts a revolving beam of light as far as the pier

Alexandra [31]

The light's coverage area is given mathematically as i.e. Area= $\pi d^{2}$