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2 years ago

Do you know how to find rate of change? X&Y intercepts? Zeros?

Mathematics

1 answer:

Rzqust [24]2 years ago

3 0

#Rate of change

Rate of change is slope

If two points be (x1,y-1) and (X2,Y2) then

Slope=m=y_2-y_1/x_2-x_1

If a line be ax+by+c=0

m=-a/b

#X and y inetercept

If a equation given y=mx+b

To find x intercept put y=0
To find y inetercept put x=0

#Zeros

To find the zeros spot out the x inetercepts

The x values of the x intercepts are the zeros

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What decimal is 1/10 of 0.08

Luden [163]

The answer is .008

Ok so lets explain this with an easier number like 1.

1 times 1/10 is 1/10 or in decimals its .1

So the decimal just got moved further back. Same thing happens with any number.

Brainliest if this helps you out?

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3 years ago

Given h(x)= 4x^2, find h(3) Help me pleasee asap

Mrrafil [7]

Answer:

Given the problem, I believe your answer would be:

h(3)=144

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Hope this helps!

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3 years ago

Read 2 more answers

Which of the following is the graph of y=sqr root -x-3

Elan Coil [88]

Answer:

The graph in the attached figure

see the explanation

Step-by-step explanation:

we have

$y=\sqrt{-x-3}$

we know that

The radicand must be greater than or equal to zero

$(-x-3)\geq 0$

solve for x

Adds 3 both sides

$-x\geq 0+3$

$-x\geq 3$

Multiply by -1 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$x\leq -3$

The domain of the function is the interval (-∞,-3]

For x=-3 ---> the value of y=0

The range is the interval {0,∞)

therefore

The graph in the attached figure

3 0

3 years ago

What is the product a2/5 (10)?

melisa1 [442]

The correct answer is 2a^2

8 0

3 years ago

I need help with this problem , GEOMETRY

34kurt

$k:\ y=m_1x+b_1\\l:\ y=m_2x+b_2\\\\k\ ||\ l\iff m_1=m_2\\\\k\ \perp\ l\iff m_1m_2=-1$

$1.\\(-6,\ 1),\ (0,\ -2)\\\\m_1=\dfrac{-2-1}{0-(-6)}=\dfrac{-3}{6}=-\dfrac{1}{2}\\\\(0,\ 3),\ (4,\ 1)\\\\m_2=\dfrac{1-3}{4-0}=\dfrac{-2}{4}=-\dfrac{1}{2}\\\\m_1=m_2\\\\Answer:\ Parallel$

$(-4,\ 0),\ (2,\ 4)\\\\m_1=\dfrac{4-0}{2-(-4)}=\dfrac{4}{6}=\dfrac{2}{3}\\\\(-3,\ 4),\ (1,\ -2)\\\\m_2=\dfrac{-2-4}{1-(-3)}=\dfrac{-6}{4}=-\dfrac{3}{2}\\\\m_1m_2=\dfrac{2}{3}\cdot\left(-\dfrac{3}{2}\right)=-1\\\\Answer:\ Perpendicular$

5 0

3 years ago