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Nataly_w [17]
3 years ago
6

4Σn=! n/n!

Mathematics
1 answer:
dusya [7]3 years ago
5 0

I think the sum is supposed to be

\displaystyle\sum_{n=1}^4\frac n{n!}=\sum_{n=1}^4\frac1{(n-1)!}

since n!=n\cdot(n-1)!. Then

\displaystyle\sum_{n=1}^4\frac1{(n-1)!}=\frac1{0!}+\frac1{1!}+\frac1{2!}+\frac1{3!}

and 0!=1 by definition so that the sum has a value of \dfrac83.

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What percent of 51 is 127.5?
kolbaska11 [484]
51 *  \frac{x}{100} = 127.5 
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51 * x = 127.5 * 100 \\ 
51*x = 12.750 \\ 
x =  \frac{12.750}{51} \\  \\ 
x = 250 


the percentage is 250
7 0
4 years ago
Which multiplication expression is equivalent to
oee [108]

Answer:

1

Step-by-step explanation:

Correct question:  2x2 - 5x - 3 / 4x2 + 12x + 5 divided by 3x2 - 11x + 6 / 6x2 + 11x - 10.

As given: \frac{(2x^{2}-5x-3) }{(4x^{2}+12x+5 )} \div \frac{(3x^{2} -11x+6)}{(6x^{2}+11x-10) }

Solving it by using quadratic equation.

= \frac{(2x^{2}-6x+1x-3) }{(4x^{2}+10x+2x+5) } \div \frac{(3x^{2}-9x-2x+6 }{(6x^{2}+15x-4x-10) }

= \frac{(2x+1) (x-3)}{(2x+1) (2x+5)} \div \frac{(3x-2) (x-3)}{(2x+5) (3x-2)}

To divide fraction take the reciprocal of divisor and multiply the dividend.

= \frac{(2x+1) (x-3)}{(2x+1) (2x+5)} \times \frac{(2x+5) (3x-2)}{(3x-2) (x-3)}

We solve it to get 1 as it cancel fraction on both side.

Answer is 1.

5 0
3 years ago
Read 2 more answers
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Makovka662 [10]
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AnnZ [28]

Answer:

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Step-by-step explanation:

4 x 4 = 16 + 9 x 2 = 43(?)

5 0
4 years ago
Is it possible to create a triangle with side lengths of 5,5 and 11 explain.
Goryan [66]

Answer:

yes

Step-by-step explanation:

just one line is going to be longer

3 0
4 years ago
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