Any point with coordinates (x, y) reflected across the y-axis is going to have the opposite x value that it did before.
You should be able to find the coordinates yourself for part a. (you didn't provide the original ones so I can't help you there)
Here is the "rule" for a reflection across the y-axis:
![(x,\ y)\rightarrow(-x,\ y)](https://tex.z-dn.net/?f=%28x%2C%5C%20y%29%5Crightarrow%28-x%2C%5C%20y%29)
And when we go 1 unit to the right and 2 down, that's the same as
![(x,\ y)\rightarrow(x+1,\ y-2)](https://tex.z-dn.net/?f=%28x%2C%5C%20y%29%5Crightarrow%28x%2B1%2C%5C%20y-2%29)
Combining those into one rule is pretty simple, Use our result for the first in the second and we would get
![(-x+1,\ y-2)](https://tex.z-dn.net/?f=%28-x%2B1%2C%5C%20y-2%29)
, so the rule is
![\boxed{(x,\ y)\rightarrow(-x+1,\ y-2)](https://tex.z-dn.net/?f=%5Cboxed%7B%28x%2C%5C%20y%29%5Crightarrow%28-x%2B1%2C%5C%20y-2%29)
.
Part A is asking for the coordinates after the reflection (x, y) ⇒ (-x, y).
Part C is asking for the coordinates after the full translation ⇒ (-x+1, y-2)