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MAVERICK [17]
4 years ago
14

Triangle ABC below is reflected across the y-axis and then translated 1 unit right and 2 units down.

Mathematics
1 answer:
hodyreva [135]4 years ago
8 0
Any point with coordinates (x, y) reflected across the y-axis is going to have the opposite x value that it did before.
You should be able to find the coordinates yourself for part a. (you didn't provide the original ones so I can't help you there)
Here is the "rule" for a reflection across the y-axis:
(x,\ y)\rightarrow(-x,\ y)
And when we go 1 unit to the right and 2 down, that's the same as
(x,\ y)\rightarrow(x+1,\ y-2)

Combining those into one rule is pretty simple, Use our result for the first in the second and we would get (-x+1,\ y-2), so the rule is
\boxed{(x,\ y)\rightarrow(-x+1,\ y-2).
Part A is asking for the coordinates after the reflection (x, y) ⇒ (-x, y).
Part C is asking for the coordinates after the full translation ⇒ (-x+1, y-2)
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The equation that is equivalent to the considered equation of log is given by: Option E: 2^3 = x+5

<h3>What is logarithm and some of its useful properties?</h3>

When you raise a number with an exponent, there comes a result.

Lets say you get a^b = c

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Some properties of logarithm are:

\log_a(b) = \log_a(c) \implies b = c\\\\\log_a(b) + \log_a(c) = \log_a(b \times c)\\\\\log_a(b) - \log_a(c) = \log_a(\frac{b}{c})\\\\\log_a(b^c) = c \times \log_a(b)\\\\\log_b(b) = 1\\\\\log_a(b) \times log_b(c) = \log_a(c)

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Log with base 10 is written as \log(x) simply.


The equation given is:

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By using the definition of log, which says a^b = c \leftrightarrow \log_a(c) = b, we get:

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Thus, the equation that is equivalent to the considered equation of log is given by: Option E: 2^3 = x+5

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Thus, the equation that is equivalent to the considered equation of log is given by: Option E: 2^3 = x+5

Learn more about logarithm here:

brainly.com/question/20835449

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