All categories

3 years ago

2/3xd=10/9 what is d

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

8 0

Answer:d=5/3x

Step-by-step explanation:

Let's solve for d.

(2/3x)(d)=10/9

Step 1: Divide both sides by (2x)/3.

2/3dx / 2x/3=10/9 / 2x/3

d=5/3x

You might be interested in

The sum of two positive integers is 67. When the smaller integer is subtracted from twice the larger, the result is 38. Find the

bixtya [17]

Answer:

Step-by-step explanation:

x+y = 67

2x-y = 38

Add the equations together

3x = 108

x = 36

y = 67-x = 31

8 0

3 years ago

Elsa drove 245 m in 4.5 h. How many hours will it take her ti drive 650 m?

Taya2010 [7]

Answer: It took 65 hours for her to drive

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

_[blank]_ show the distribution and frequency for a set of values. _[blank]_ is how the values are spread out or grouped, and _[

snow_lady [41]

I think it's histograms for the first blank; distribution for the second blank; frequency for the third and final blank.

Hope this helps please let me know if I'm wrong :)))

8 0

3 years ago

PLZ HELP, GIVING BRAINLIEST!!

givi [52]

The area of triangle B is 10.5 square units.

The area of triangle C is 10 square units.

Step-by-step explanation:

Step 1:

The area of a triangle is half the product of its base length and height.

The base is the lower end of the triangle and its length is called base length.

The length from the base to the highest point on the triangle is the height.

Step 2:

For triangle B, the base extends for a length of 7 units and the height is 3 units.

The area of triangle B $= \frac{1}{2} (b)(h) = \frac{1}{2} (7)(3) = \frac{21}{2} = 10.5,$

So the area of triangle B is 10.5 square units.

Step 3:

For triangle C, the base extends for a length of 5 units and the height is 4 units.

The area of triangle C $= \frac{1}{2} (b)(h) = \frac{1}{2} (5)(4) = \frac{20}{2} = 10,$

So the area of triangle C is 10 square units.

5 0

3 years ago

Let C be the closed, piecewise smooth curve formed by traveling in straight lines between the points (-2,1), (-2,-3), (1,-1) , (

Greeley [361]

The given points are the vertices of the quadrilateral

$Q=\left\{(x,y)\mid-2\le x\le1,\dfrac{2x-5}3\le y\le\dfrac{4x+11}3\right\}$

By Green's theorem, the line integral is

$\displaystyle\int_C2xy\,\mathrm dx+xy^2\,\mathrm dy=\iint_Q\frac{\partial(xy^2)}{\partial x}-\frac{\partial(2xy)}{\partial y}\,\mathrm dA$

$=\displaystyle\int_{-2}^1\int_{(2x-5)/3}^{(4x+11)/3}y^2-2x\,\mathrm dy\,\mathrm dx=\boxed{61}$

6 0

3 years ago