All categories

2 years ago

HELP PLEASE HAVING BAD DAY

Mathematics

2 answers:

Marta_Voda [28]2 years ago

6 0

Answer:

I need to know how fast the driver is going

Step-by-step explanation:

Airida [17]2 years ago

5 0

Answer:

12/s

Step-by-step explanation:

You might be interested in

What is the solution to 1< 25-4x<19?

koban [17]

Hope this helps

Hope you have a good day

4 0

3 years ago

It takes you 45 minutes to clean the fish tank and it takes your sister 30 minutes. how long does it take the two of you working

katen-ka-za [31]

It takes you 45 minutes to clean the fish tank and it takes your sister 30 minutes. how long does it take the two of you working together to clean the fish tank

Answer:

My 1 minute work = $\frac{1}{45}$

My sisters 1 minute work = $\frac{1}{30}$

My and My sister's 1 minute work = $\frac{1}{45}+\frac{1}{30}$

= $\frac{5}{90}$

= $\frac{1}{18}$

$\therefore$ Me and My sister will finish the work in $\frac{18}{1} =18$ minutes

5 0

2 years ago

Find the value of each expression.<br> -5 -9 -13

Andrei [34K]

Answer:

-27

Step-by-step explanation:

-5-9=-14

-14-13=-27

3 0

3 years ago

Find the solution set of the following quadratic equations using the quadratic formula.

oksian1 [2.3K]

Answer:

<h3> 1) $x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$ </h3><h3> 2) $x_1=-\dfrac13\,,\quad x_2=-3$ </h3>

Step-by-step explanation:

$x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$

<h3>2)</h3><h3> $3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3$ </h3>

7 0

3 years ago

The function f(x)=-10(x)(x-4) represents the approximate height of a projectile launch on the ground into the air as a function

ELEN [110]

Answer:

4 seconds.

Step-by-step explanation:

The function f(x)=-10(x)(x-4) ........ (1), represents the approximate height of a projectile launch on the ground into the air as a function of time in seconds x.

Now, we are asked that for how long from the launch does the projectile stays in the air.

Therefore, we have to solve the equation (1) making f(x) as zero.

Hence, 10x(x - 4) = 0

⇒ x = 0 or x = 4

(As x can not be zero since at x = 0 sec, the projectile was at the ground.}

Hence, x = 4 seconds.

Therefore, the projectile was in the air for 4 seconds. (Answer)

4 0

3 years ago

Read 2 more answers