Question

If s(x) = 2 – x2 and t(x) = 3x, which value is equivalent to (sxt)(-7)?

Answer 1

(s o t)(-7) = s(t(-7)) = s(3(-7)) = s(-21) = 2 - (-21)^2 = 2 - 441 = -439

Answer 2

Step-by-step explanation:

$s(x)= 2-x^2$

$t(x)= 3x$

To find $(sot)(-7)= s(t(-7))$

First we find t(-7) and then we plug it in s(x)

$t(x)= 3x$, plug in -7 for x

$t(-7)= 3(-7)=-21$

$(sot)(-7)= s(t(-7))=s(-21)$, plug in -21 for x in s(x)

$s(-21)= 2-(-21)^=-439$

$(sot)(-7)= s(t(-7))=-439$

If we are given with (s times t)(-7) we multiply it

$(s \cdot t)(-7)= s(-7) \cdot t(-7)$

t(-7) is -21

$s(-7)= 2-(-7)^2= -47$

$(s \cdot t)(-7)= s(-7) \cdot t(-7)=-21 \cdot (-47)=987$