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3 years ago

8

Which graph represents the solution set of the compound inequality -4≤3x-1 and 2x+4≤18?

2 answers:

Lana71 [14]3 years ago

8 0

Answer:

the answer would be the first number line so A...................

Step-by-step explanation:

Bond [772]3 years ago

4 0

Answer:

can you put the pic of the graph plzz

Step-by-step explanation:

thx

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Two sides of a triangle measure 5 inches and 9 inches. Which of the following is a measure of a possible 3rd side of the triangl

svet-max [94.6K]

Answer:

B. 5 inches

Step-by-step explanation:

This is because of the triangle inequality theorem which states "The sum of the lengths of any two sides of a triangle is greater than the length of the third side." So, since 5+9 is 14 it has to be less than 14. Also, because 5+2 is 7 and that is not greater than 9 it has to be 5 inches.

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3 years ago

Read 2 more answers

Find the exact length of the third side

Mumz [18]

Answer:

5

Step-by-step explanation:

We know that 13 is the hypotenuse. With this we can use the Pythagorean Theorem to solve this problem.

Let the third side be x.

13^2=12^2+x^2

169=144+x^2

169-144=x^2

25=x^2

x=5

Solved.

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3 years ago

Find the values of the variables.

iris [78.8K]

Answer:

x=-1/2

Step-by-step explanation:

2x+2=4x+3

-1=2x

x=-1/2

3 0

3 years ago

-3/8p=9 how do you isolate p?

LenKa [72]

Answer:

multiply both sides by 8 then divide by -3

or in one step divide both sides by (-3/8) which is the same as multiplying by

(-8/3)...

-3p = 72

p = -24

Step-by-step explanation:

5 0

3 years ago

One end of a line segment has the coordinates (-6,2). If

CaHeK987 [17]

Answer:

The coordinates of the other end is $(16,2)$

Step-by-step explanation:

Given

$End 1: (-6,2)$

$Midpoint: (5,2)$

Required

Find the coordinates of the other end

Let Midpoint be represented by (x,y);

(x,y) = (5,2) is calculated as thus

$(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$

So

$x = \frac{x_1 + x_2}{2}$ and $y = \frac{y_1 + y_2}{2}$

Where $(x_1,y_1) = (-6,2)$ and $(x,y) = (5,2)$

So, we're solving for $(x_2,y_2)$

Solving for $x_2$

$x = \frac{x_1 + x_2}{2}$

Substitute 5 for x and -6 for x₁

$5 = \frac{-6 + x_2}{2}$

Multiply both sides by 2

$2 * 5 = \frac{-6 + x_2}{2} * 2$

$10 = -6 + x_2$

Add 6 to both sides

$6 + 10 = -6 +6 + x_2$

$x_2 = 16$

Solving for $y_2$

$y = \frac{y_1 + y_2}{2}$

Substitute 2 for y and 2 for y₁

$2 = \frac{2 + y_2}{2}$

Multiply both sides by 2

$2 * 2 = \frac{2 + y_2}{2} * 2$

$4 = 2 + y_2$

Subtract 2 from both sides

$4 - 2 = 2 - 2 + y_2$

$y_2 = 2$

$(x_2,y_2) = (16,2)$

Hence, the coordinates of the other end is $(16,2)$

3 0

3 years ago