Answer:
1,805 kg.
Step-by-step explanation:
We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.
First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.
Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.
Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.
Answer:
|4X + 6|
Step-by-step explanation:
● Answer:
8.995 cm
● Step-by-step explanation:
P = d + L/2
d = 3.5 cm
L/2 = 2pi×r/2
= pi×d/2
= 3.14×3.5/2
= 5.495 cm
P = 3.5cm + 5.495
= 8.995 cm
Answer: Look at step by step
Step-by-step explanation:
(a) There are 119 stocks that increased in price out of 246 stocks so the probability of selecting a stock that is increased in price is 119/246 = 48.37%
(b) There are 112 stocks where it pays dividends so the probability so the probability of selecting a stock that pays dividends is 112/246 = 45.53%
(c) There are 49 stocks which satisfy the question so the probability is 49/246 = 19.92%
(e) There are 34 stocks which increase in price and pay dividends out of the 119 stocks that increase in price so the probability is 34/119 = 28.57%
(f) Using the same logic as (e), the probability is 85/134 = 63.43%
(g) From the requirements, we see that 49 stocks don't satisfy the requirements, so the probability is (246-49)/246 = 80.08%
