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4 years ago

6xy in simplest form

Mathematics

1 answer:

nikklg [1K]4 years ago

4 0

6xy is already in simplest form, unless a typo has occurred in your question.

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Can you help me please ?

rusak2 [61]

Answer:

C. :)

Hope it helps

Step-by-step explanation:

8 0

3 years ago

1. A flower shop wishes to add the valuable Waimea orchid to its product list. They purchase a large shipment of bulbs from a su

AysviL [449]

Answer:

The concern of the florist that these bulbs are not Waimea orchids, but a similar appearing hybrid maybe true.

Step-by-step explanation:

A Chi-square goodness of fit test can be used to perform the hypothesis test.

The hypothesis is defined as:

<em>H</em>₀: There is no difference between the observed and expected value.

<em>Hₐ</em>: There is a difference between the observed and expected value.

The test statistic is:

$\chi^{2}=\sum \frac{(O-E)^{2}}{E}$

The total number of Waimea orchid bulbs is, 60.

7x + 5x + 4x + 4x = 60

20x = 60

x = 3

The expected number of Waimea orchid bulbs are:

Blue = 7 × 3 = 21

Red = 5 × 3 = 15

Violet = 4 × 3 = 12

Orange = 4 × 3 = 12

Consider the table provided.

The test statistic value is:

$\chi^{2}=\sum \frac{(O-E)^{2}}{E}=14.981$

The decision rule:

The null hypothesis will be rejected if $\chi^{2}\geq \chi^{2}_{\alpha, (k-1)}$ .

Compute the critical value as follows:

$\chi^{2}_{0.05, (4-1)}= \chi^{2}_{0.05, (3)}=7.815$

The test statistic value is 14.981.

$\chi^{2}=14.981> \chi^{2}_{\alpha, (k-1)}=7.815$

The null hypothesis will be rejected at 5% level of significance.

Conclusion:

As the null hypothesis was rejected it implies that there is a significant difference between the observed and expected value.

Thus, the concern of the florist that these bulbs are not Waimea orchids, but a similar appearing hybrid maybe true.

4 0

4 years ago

Small sample: During an economic downturn, companies were sampled and asked whether they were planning to increase their workfor

leva [86]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The confidence level interval is $0.016 \le C \le 0.404$

Step-by-step explanation:

The sample size is $n = 20$

The number planning to increase workforce is $x = 3$

The confidence level is $c = 98$ %

The value of proportion for a plus 4 method is

$p = \frac{x+2}{n+4}$

substituting values

$p = \frac{3+2}{20+4}$

$p =0.21$

The z-critical value at confidence level of 98% is

$z_{c}=z_{0.98} = 2.33$

This values is obtained from the standard normal table

The confidence level interval can be mathematically represented as

$C =p \ \pm z_{c} * \sqrt{\frac{p(1-p)}{n+4} }$

substituting values

$C = 0.21 \pm 2.33 * \sqrt{\frac{0.21(1- 0.21)}{20 +4} }$

$C = 0.21 \pm 0.194$

=> $0.016 \le C \le 0.404$

7 0

3 years ago

Please Help me PLLLEEEAAASSSEEEEE

-BARSIC- [3]

Answer:

A quadrilateral become square if all the sides joining the co-ordinate of quadrilateral is equal

Step-by-step explanation:

Here the given co-ordinate of quadrilateral are

G (3, -1) O(1, -6)

L(-4, -4) F(-2, 1)

Line GF = $\sqrt{(3+2)^2+(-1-1)^2}$

GF = $\sqrt{29}$

Similarly for line OG, OL, FL

OG = $\sqrt{(1-3)^2 +(-6+1)^2$

OG = $\sqrt{29}$

OL = $\sqrt{(-4-1)^2+(-6+4)^2}$

OL = $\sqrt{29}$

And

FL = $\sqrt{(-4+2)^} +(-4+1)^2$

FL = $\sqrt{29}$

all the sides of quadrilateral GF, OG, OL, FL all equal to $\sqrt{29}$

As all the sides are equal so quadrilateral become square Answer

3 0

3 years ago

A painter charges $15.07 per hour, plus an additional amount for the supplies. If he made $170.83 on a job where he worked 6 hou

irina [24]

The supplies cost $80.41. I also attached a picture of the work in case you need it

6 0

4 years ago