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2 years ago

How do I put -(x-4)^2 -1 into standard form

1 answer:

4 0

Standard form is ax²+bx+c

expand then simlify
-(x-4)²=-(x-4)(x-4)=-(x²-8x+16)=-x²+8x-16
now we gots
-x²+8x-16-1
-x²+8x-17 is standard form

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Greeley [361]

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2 years ago

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Dimas [21]

Answer:

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Step-by-step explanation:

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2 years ago

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3 years ago

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murzikaleks [220]

Answer:

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Step-by-step explanation:

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1 year ago