How do I put -(x-4)^2 -1 into standard form

1 answer:

4 0

Standard form is ax²+bx+c

expand then simlify
-(x-4)²=-(x-4)(x-4)=-(x²-8x+16)=-x²+8x-16
now we gots
-x²+8x-16-1
-x²+8x-17 is standard form

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