3 years ago

How do I put -(x-4)^2 -1 into standard form

1 answer:

4 0

Standard form is ax²+bx+c

expand then simlify
-(x-4)²=-(x-4)(x-4)=-(x²-8x+16)=-x²+8x-16
now we gots
-x²+8x-16-1
-x²+8x-17 is standard form

You might be interested in

Sauron [17]

Answer: Can you translate for me? I don't know spanish.

Step-by-step explanation:

8 0

3 years ago

Vesna [10]

Hello! Its really simple 16 ounces equal 1 pound!

8 0

3 years ago

iren [92.7K]

Answer:

The answer to this question is 40

8 0

3 years ago

Katen [24]

Answer:

I think that there is indefinite.

Step-by-step explanation:

The reason why is because <em>x and y </em>could be any number

6 0

3 years ago

Kaylis [27]

Answer:

D : One Real Root

Step-by-step explanation:

Isolate "4x" by subtracting 7 from both sides.

So we get

4x = -7

Then we divide each side by 4 to get -7/4

x = -7/4 so there is only one real root.

5 0

3 years ago