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4 years ago

Write 6,219 in expanded form.

Mathematics

2 answers:

zhenek [66]4 years ago

4 0

Answer: 6000+200+10+9

Step-by-step explanation:

The ones place multiplies by 1 so 9*1=9

The tens place multiplies by 10 so 10*1=10

The hundreds place multiply by 100 so 100+2=100

The thousands place multiply by 1000 so 1000*6=6000

Hope This Helps!!!

Alex17521 [72]4 years ago

3 0

6000+200+10+9=6219 expanded

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Answer:

Let's assume the following data:

Price in Dollars (X) 26 29 32 38 47

Number of Bids (Y) 12 13 15 16 18

For our case we have this:

n=10 $\sum x = 172, \sum y = 74, \sum xy = 2623, \sum x^2 =6194, \sum y^2 =1118$

$r=\frac{5(2623)-(172)(74)}{\sqrt{[5(6194) -(172)^2][5(1118) -(74)^2]}}=0.974$

So then the correlation coefficient would be r =0.974

Step-by-step explanation:

Previous concepts

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

Solution to the problem

And in order to calculate the correlation coefficient we can use this formula:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

Let's assume the following data

Price in Dollars (X) 26 29 32 38 47

Number of Bids (Y) 12 13 15 16 18

For our case we have this:

n=10 $\sum x = 172, \sum y = 74, \sum xy = 2623, \sum x^2 =6194, \sum y^2 =1118$

$r=\frac{5(2623)-(172)(74)}{\sqrt{[5(6194) -(172)^2][5(1118) -(74)^2]}}=0.974$

So then the correlation coefficient would be r =0.974

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