Solving equations with one variable

Mathematics

1 answer:

kupik [55]3 years ago

5 0

Answer:

1) b= -20

Step-by-step explanation:

You bring the variable you want to find to one side by either bringing over the second term to the other side of the equation and change its sign or if it's a fraction you multiply both sides to remove the denominator and then solve

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If f(x) = x^2 - x, what is f(-3)?

myrzilka [38]

F(-3) = (-3)^2 - (-3) = 9 - (-3) = 9 + 3 = 12

8 0

3 years ago

A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an

denis-greek [22]

Let $x$ be the distance from the left wall to the laser source and $y$ the distance form the right wall to the laser source.

We can use the cosine trigonometric function in the smaller triangle to relate the adjacent side of the angle and the hypotenuse; then we can solve for $x$ :
$cos( \alpha )= \frac{adjacent.side}{hypotenuse}$
$cos(60)= \frac{x}{40}$
$x=40cos(60)$
$x=20m$

We can use the tangent trigonometric function in the larger triangle to relate the opposite side of the angle and its adjacent side; then we can solve for $y$ :
$tan( \alpha )= \frac{opposite.side}{adjacent.side}$
$tan(45)= \frac{80}{y}$
$y= \frac{80}{tan(45)}$
$y=80m$

Now we can add both distances:
$20m+80m=100m$

We can conclude that <span>the distance between the walls is 100 m.</span>